我创建了一个twitter.Twitter对象,但无法将其存储到会话中。以下是我的代码。
t = twitter.Twitter(auth=twitter.OAuth(consumer_key, consumer_secret,
oauth_token, oauth_secret))
request.session['t'] = t
但如果我存储像
这样的字符串request.session['t'] = 't'
它有效,为什么?因为twitter #Twitter对象不是可序列化的对象?每次需要twitter #Twitter对象时,如何避免进行身份验证?以下是django追踪。
Django Version: 1.3.1
Python Version: 2.6.6
Installed Applications:
['django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.sites',
'django.contrib.messages',
'django.contrib.staticfiles',
'myproj.myapp']
Installed Middleware:
('django.middleware.common.CommonMiddleware',
'django.contrib.sessions.middleware.SessionMiddleware',
'django.middleware.csrf.CsrfViewMiddleware',
'django.contrib.auth.middleware.AuthenticationMiddleware',
'django.contrib.messages.middleware.MessageMiddleware')
Traceback:
File "/usr/lib/python2.6/site-packages/django/core/handlers/base.py" in get_response
178. response = middleware_method(request, response)
File "/usr/lib/python2.6/site-packages/django/contrib/sessions/middleware.py" in process_response
36. request.session.save()
File "/usr/lib/python2.6/site-packages/django/contrib/sessions/backends/file.py" in save
121. os.write(output_file_fd, self.encode(session_data))
File "/usr/lib/python2.6/site-packages/django/contrib/sessions/backends/base.py" in encode
93. pickled = pickle.dumps(session_dict, pickle.HIGHEST_PROTOCOL)
File "/usr/lib/python2.6/site-packages/twitter-1.9.0-py2.6.egg/twitter/api.py" in __call__
173. return self._handle_response(req, uri, arg_data)
File "/usr/lib/python2.6/site-packages/twitter-1.9.0-py2.6.egg/twitter/api.py" in _handle_response
198. raise TwitterHTTPError(e, uri, self.format, arg_data)
Exception Type: TwitterHTTPError at /tool/log_in/
Exception Value:
答案 0 :(得分:0)