Question

我有这段代码：

class USerializer {
public:
    template<typename T>
    static std::string serialize(std::list<T*> listOfObjectToSerialize)
    {
        // stringstream containing serialized Objects
        std::stringstream serializedObjectList;

        typename std::list<T*>::iterator iter;

        // serialize Objects
        for (iter = listOfObjectToSerialize.begin(); iter != listOfObjectToSerialize.end(); ++iter)
        {
            // Class delimiter
            serializedObjectList << '+'<< endl;

            // Need to serialise the class itself, and not the pointer to it!
            serializedObjectList << **iter;
        }

        return serializedObjectList.str();
    }
}

然后我使用这样的方法：

std::string serializedAlarmInfo = USerializer::serialize<CcAlarm::AlarmInfo>(getActiveAlarms());

我收到了SIGILL错误：

Program received signal SIGILL, Illegal instruction.

使用gdb我跟踪执行，一切似乎都没问题，直到我退出序列化函数。

有什么想法吗？

Answer 1

尝试：

if ((*iter) == NULL)
{    throw std::runtime_error("Was not expecting that");
}
// Or use some other technique to compensate for a NULL pointer.
serializedObjectList << **iter;

std :: string中的非法指令

1 个答案: