Question

我的输入是

char *str = "/send 13 01 09 00";

我需要输出为

BYTE* result = { 0x13, 0x09, 0x00 };

（所以跳过/发送）

有人可以为我提供从十六进制字节字符串中获取字节的解决方案吗？

这是我尝试过的：

#include "stdafx.h"
#include <iostream>
#include <windows.h>
#include <conio.h>
#include <string>

byte *ToPacket(const char* str)
{
    const char *pos = str;
    unsigned char val[sizeof(str)/sizeof(str[0])];

    size_t count = 0;

    for(count = 0; count < sizeof(val)/sizeof(val[0]); count++)
    {
        sscanf_s(pos, "%2hhx", &val[count]);
        pos += 2 * sizeof(char);
    }

    return val;
}

int _tmain(int argc, _TCHAR* argv[])
{

redo:

    while (true)
    {
        std::string key;
        std::getline(std::cin, key); 

        if (key != "")
        {
            if (key == "/hit")
            {
                BYTE packet[] = { 0x13, 0x01, 0x00 };
                int size = sizeof(packet) / sizeof(packet[0]);              

                std::cout << "[FatBoy][" << key << "]: Hit\n";
            }
            else if (strstr(key.c_str(), "/send"))
            {
                BYTE * packet = ToPacket(key.c_str());
                int size = sizeof(packet) / sizeof(packet[0]);

            }


            key = "";
            break;
        }

        Sleep(100);
    }
    goto redo; 
}

Answer 1

#include <iostream>
#include <sstream>
#include <string>
#include <iomanip>

std::string s("/send 13 01 09 00");
int v1,v2,v3,v4;
std::string cmd;
std::istringstream inp_stream(s);
inp_stream >> cmd >> std::setbase(16) >> v1 >> v2 >> v3 >> v4;

Answer 2

使用std::istringstream与std::hex IO操纵器填充std::vector<unsigned char>：

std::string s("13 01 09 00");
std::vector<unsigned char> v;
std::istringstream in(s);
in >> std::hex;

unsigned short c;
while (in >> c) v.push_back(static_cast<unsigned char>(c));

请参阅http://ideone.com/HTJmzJ上的演示。

十六进制到十六进制字节的字符

2 个答案: