我是mysqli的新手,并且遇到了使用mysqli循环结果的问题。不幸的是,我只得到了一个结果。当我将查询放入phpMyAdmin时,它会得到三个结果。我相信相关的代码在这里,我只是称错了:
$connection = new mysqli($host, $databaseUsername, $databasePassword, $database);
if ($connection->connect_errno > 0) {
die ('Unable to connect to database [' . $connection->connect_error . ']');
}
$sql = "SELECT clientId, studentFirstName, studentLastName
FROM clients
WHERE (studentEmail = '$postEmail') OR (parentEmail = '$postEmail');";
if (!$result = $connection->query($sql)) {
die ('There was an error running query[' . $connection->error . ']');
}
echo '<select class = "toolbarDropdown" id = "toolbarDropdown-MultipleAccounts">';
while ($row = $result->fetch_array()) {
echo '<option value="'.$row["clientId"].'">'.$row["studentFirstName"].' '.$row["studentLastName"].'</option>';
}
echo '</select>';
答案 0 :(得分:15)
您在HTML
中缺少结束“at option =”值&lt; -请注意
$row = $result->fetch_array()
可以替换为
$row = $result->fetch_assoc()
这样做,你获取的每个记录的数组将占用一半的大小。