在存储过程中从双分隔字符串创建表

Question

给定存储过程的输入值，如下所示：

264#20,241#15,228#10

如何将其转换为如下表格？

ID1     ID2
264     20
241     15
228     10

由于

Answer 1

您可以在存储过程中使用类似的内容：

;with cte (item, col1) as
(
  select 
    cast(left(col1, charindex(',',col1+',')-1) as varchar(50)) item,
         stuff(col1, 1, charindex(',',col1+','), '') col1
  from yourtable
  union all
  select 
    cast(left(col1, charindex(',',col1+',')-1) as varchar(50)) item,
    stuff(col1, 1, charindex(',',col1+','), '') col1
  from cte
  where col1 > ''
),
s2 (id1, id2) as
(
  select substring(item, 1, charindex('#', item)-1), 
    reverse(substring(reverse(item), 1, charindex('#', reverse(item))-1))
  from cte
)
select id1, id2
from s2

请参阅SQL Fiddle with Demo

结果：

| ID1 | ID2 |
-------------
| 264 |  20 |
| 241 |  15 |
| 228 |  10 |