在java中读取日志文件

时间:2012-12-18 14:12:51

标签: java fileinputstream logfile

是否可以使用java读取日志文件(abc.log)?

我想从我的日志文件中获取特定字符串。

假设这是我的日志文件的内容。我只想要时间戳(例如:05:08:37)并将其打印到控制台。

2012-12-16 05:08:37,905 [Thread-1] INFO  com.submit.SubmitService - Wait time 500

2012-12-16 05:08:38,444 [Thread-1] INFO  com.submit.SubmitService - NO OF  RECORDS TILL NOW 3755    TOTAL TIME -- << 539

2012-12-16 05:08:38,668 [Thread-1] INFO  com.submit.SubmitService - Active Connection:: -69076

2012-12-16 05:08:38,670 [Thread-1] INFO  com.submit.SubmitService - Active Connection:: -65764

2 个答案:

答案 0 :(得分:5)

您可以将“日志文件”作为普通文件阅读。

然后你可以使用regular expression来获取你需要的字符串部分:

try{
   FileInputStream fstream = new FileInputStream("abc.log");
   BufferedReader br = new BufferedReader(new InputStreamReader(fstream));
   String strLine;
   /* read log line by line */
   while ((strLine = br.readLine()) != null)   {
     /* parse strLine to obtain what you want */
     System.out.println (strLine);
   }
   fstream.close();
} catch (Exception e) {
     System.err.println("Error: " + e.getMessage());
}

答案 1 :(得分:-1)

导入java.io.File;导入java.io.FileNotFoundException; importjava.util.Scanner; 导入java.sql。*;

公共类ReadingEntireFileWithoutLoop {

public static void main(String[] args) throws FileNotFoundException {

    File file = new File("X:\\access.log");

    Scanner sc = new Scanner(file);
    sc.useDelimiter(",|\r\n");
    System.out.println(sc.next());
    while(sc.hasNext()){
        System.out.println(sc.next());
        }
        // closing the scanner stream
        sc.close();
}