Question

我正在尝试将图片网址写入一个将写入zip并强制下载的数组

当我写下面的数组时

$images= array(
    'http://distilleryimage10.s3.amazonaws.com/de532c02488c11e2b62722000a1fbc10_7.jpg',
    'http://distilleryimage10.s3.amazonaws.com/8b9b59e848fb11e2b39e22000a9d0df1_7.jpg'
);

除了本期底部的大型脚本外，zip下载还不错。

但是当我使用以下

时

foreach ($response['data'] as $data) {
    $images[] = $data['images']['standard_resolution']['url'];
}

zip下载但有一个弹出窗口说zip无效。创建数组的foreach只写入url。

下载zip包的代码

# create new zip opbject
$zip = new ZipArchive();

# create a temp file & open it
$tmp_file = tempnam('.','');
$zip->open($tmp_file, ZipArchive::CREATE);

    # loop through each file
    foreach($images as $image){
        # download file
        $download_file = file_get_contents($image);
        #add it to the zip
        $zip->addFromString(basename($image),$download_file);   
    }

    # close zip
    $zip->close();

    # send the file to the browser as a download

    header('Content-disposition: attachment; filename=download.zip');
    header('Content-type: application/zip');
    readfile($tmp_file);

如果有人能帮助我，我会很感激，因为我很难坚持这个

Answer 1

阵列不是我的事，但我认为：

# loop through each file
foreach($images as $key=>$value){
    # download file
    $download_file = file_get_contents($value);
    #add it to the zip
    $zip->addFromString(basename($value),$download_file);   
}

创建一个以zip格式下载的数组

1 个答案: