Question

我有2个表（THour_IN和THour_OUT）具有相同的模式： THour_IN的列：名称|日期| HourIN Colour for THULL_OUT：名称|日期|小时我查询：

SELECT THour_IN.Name, THour_IN.date, THour_IN.HourIN, THour_OUT.HourOUT FROM THour_IN LEFT JOIN THour_OUT ON (Hour_IN.Name = THour_OUT.Name) AND (Hour_IN.date = THour_OUT.date);

但在我的情况下这是不正确的，因为我在表中的同一日期有多行。结果是：

Name   date       HourIN    HourOUT
AAA 24/11/2013  17:33:06    20:33:27
AAA 24/11/2013  17:33:06    16:36:06
AAA 24/11/2013  07:33:27    20:33:27
AAA 24/11/2013  07:33:27    16:36:06
BBB 18/11/2013              16:36:06
BBB 19/11/2013  07:33:30    
BBB 21/11/2013  07:29:24    08:33:22
BBB 22/11/2013  07:33:30    16:34:53

应该是日期24/11/2013 First HourIN（07:33:27）与Fisrt HourOUT（16:36:06），Second HourIN（17:33:06）with Second HourOUT（20:33： 06）有什么想法吗？

Answer 1

构建细分，然后交叉细分。

SELECT
  P1.Name, P1.date, P1.HourIN, P1.HourOUT
FROM (
  SELECT
    I.Name, I.date, I.HourIN, O.HourOUT
  FROM
    THour_IN AS I
    LEFT JOIN THour_OUT AS O
      ON (I.Name = O.Name) AND (I.date = O.date)
        AND I.HourIN < H.HourOUT
) AS P1
INNER JOIN (
  SELECT
    I.Name, I.date, I.HourIN, O.HourOUT
  FROM
    THour_IN AS I
    LEFT JOIN THour_OUT AS O
      ON (I.Name = O.Name) AND (I.date = O.date)
        AND I.HourIN < H.HourOUT
) AS P2
  ON P1.name = P2.name AND P1.date = P2.date
    AND P1.HourIN <> P2.HourIN and P1.HourOUT <> P2.HourOUT
    AND P1.HourOUT > P2.HourIN
    AND (P1.HourIN = P2.HourIN AND P1.HourOUT < P2.HourOUT
          OR P1.HourIN > P2.HourIN AND P1.HourOUT = P2.HourOUT)

Answer 2

您可以使用类似的东西：

SELECT
  t.Name, 
  t.Date, 
  t.HourIN, (
     SELECT Top 1 HourOut 
     FROM THourOUT o 
     WHERE o.Name=t.Name AND o.Date=t.date And o.HourOUT>t.HourIN 
     ORDER BY o.HourOUT,o.ID ) AS HrOut
FROM THourIN AS t
ORDER BY t.Date, t.HourIN;

请注意，我已在OUT表中添加了一个ID，以确保top 1不会返回重复项。

以下是插入缺失值的示例。它取决于一个Numbers表，其中包含从0或1到最大缺失值的整数。数字表在很多方面都很有用。

INSERT INTO thourin
            (name,
             [date])
SELECT q.name,
       q.DATE
FROM   (SELECT Outs.name,
               Outs.DATE,
               Outs.countofout,
               Ins.countofin
        FROM   (SELECT o.name,
                       o.DATE,
                       Count(o.name) AS CountOfOut
                FROM   thourout o
                GROUP  BY o.name,
                          o.DATE) AS Outs
               LEFT JOIN (SELECT t.name,
                                 t.DATE,
                                 Count(t.name) AS CountOfIn
                          FROM   thourin t
                          GROUP  BY t.name,
                                    t.DATE) AS Ins
                      ON ( Outs.name = Ins.name )
                         AND ( Outs.DATE = Ins.DATE )
        WHERE  (( ( Ins.countofin ) <> [countofout]
                   OR ( Ins.countofin ) IS NULL ))) AS q,
       numbers AS n
WHERE  (( ( n.counter ) > 0
          AND ( n.counter ) <= [countofout] - [countofin] ))

从第二个表中选择具有条件的查询

2 个答案: