我正在尝试运行高级Linux编程手册(清单3.4,第51页)中的示例:
#include <stdio.h>
#include <stdlib.h>
#include <sys/types.h>
#include <unistd.h>
/* Spawn a child process running a new program. PROGRAM is the name
of the program to run; the path will be searched for this program.
ARG_LIST is a NULL-terminated list of character strings to be
passed as the program’s argument list. Returns the process ID of
the spawned process. */
int spawn(char* program, char** arg_list) {
pid_t child_pid;
/* Duplicate this process. */
child_pid = fork();
if (child_pid != 0)
/* This is the parent process. */
return child_pid;
else {
/* Now execute PROGRAM, searching for it in the path. */
execvp(program, arg_list);
/* The execvp function returns only if an error occurs. */
fprintf(stderr, "an error occurred in execvp\n");
abort();
}
return 0;
}
int main() {
/* The argument list to pass to the "ls” command. */
char* arg_list[] = { "ls", /* argv[0], the name of the program. */
"-l", "/", NULL /* The argument list must end with a NULL. */
};
/* Spawn a child process running the "ls” command. Ignore the
returned child process ID. */
spawn(" ls", arg_list);
printf("done with main program\n");
return 0;
}
我得到了:
an error occurred in execvp
done with main program
知道这里有什么问题吗? (使用Ubuntu 10.10)
答案 0 :(得分:2)
根据汤姆的要求:
问题似乎是字符串中命名命令的(额外)空间。
请记住,您没有调用 bash (shell)解释器并为其提供字符串命令。您正在“命名”命令,在这方面,它类似于命名文件,在与可用命令(文件)进行比较时会考虑所有字符。
答案 1 :(得分:1)
快速猜测,无需验证:您必须提供ls命令的完整路径,例如/ bin / ls
答案 2 :(得分:1)
传递给spawn函数的“program”参数不正确。由execvp的手册页指定:
这些函数的初始参数是要执行的文件的名称。
此处您要执行的文件是/ bin / ls