hibernate Criteria API有很多对很多

Question

TaskCategory.hbm.xml

<hibernate-mapping>
        <class name="TaskCategory" table="TASK_CATEGORY" select-before-update="true">
            <id name="taskCategoryId" type="integer">
                <column name="TASK_CATEGORY_ID" />
                <generator class="identity" />
            </id>
            <property name="taskCategory" type="string">
                <column name="TASK_CATEGORY" length="512" not-null="true" />
            </property>
            <property name="taskCategoryGroup" type="string">
                <column name="TASK_CATEGORY_GROUP" length="32" not-null="true" />
            </property>
            <property name="description" type="string">
                <column name="DESCRIPTION" length="255" />
            </property>

            <set name="jurisdictions" inverse="true" table="task_category_jurisdiction">
                <key>
                    <column name="task_category_id" not-null="true" />
                </key>
                <many-to-many entity-name="com.sterling.ag.model.Jurisdiction">
                    <column name="jurisdiction_ID" not-null="true" />
                </many-to-many>
            </set>
        </class>
    </hibernate-mapping>

Jurisdiction.hbm.xml

<hibernate-mapping default-access="field">
<class name="Jurisdiction" table="Jurisdiction">
    <id name="jurisdictionId" type="int">
        <column name="Jurisdiction_ID" />
        <generator class="identity" />
    </id>
    <many-to-one name="jurisdictionType" class="JurisdictionType" fetch="select">
        <column name="Jurisdiction_Type_ID" not-null="true" />
    </many-to-one>

     <one-to-one name="flattenedJurisdiction" class="FlattenedJurisdiction" />

    <set name="taskCategories" table="task_category_jurisdiction" fetch="select">
        <key>
            <column name="jurisdiction_id" not-null="true" />
        </key>
        <many-to-many entity-name="TaskCategory">
            <column name="task_category_id" not-null="true" />
        </many-to-many>
    </set>      
</class>

我想实现这样的目标：

 whereClause.append(" and a.jurisdiction_id not in (select distinct   (j.jurisdiction_id) from " +
                        "task_category_jurisdiction j)" );

还有另一个包含管辖权的“a”的Hibernate文件。 where子句是StringBuffer。

我试过这个：

DetachedCriteria dc1 = DetachedCriteria.forClass(TaskCategory.class);
dc1.setProjection(Projections.distinct(Projections.property("jurisdictions")));
criteriaQuery.add(Restrictions.not(Subqueries.in("a.jurisdiction", dc1)));