Question

我通过构建输入SOAP并作为请求发送来从android调用.net XML Web服务。接收响应为XML字符串并解析它。以上所有工作正常。

为了构建XML字符串，我正在使用DocumentBuilderFactory这样的示例

DocumentBuilderFactory documentBuilderFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder documentBuilder = documentBuilderFactory.newDocumentBuilder();
Document document = documentBuilder.newDocument();

Element rootElement = document.createElement("XMLINPUT");//Parent Node of the xml
document.appendChild(rootElement);

Element childElementCNN = document.createElement("CNNREFF");//Child Node
rootElement.appendChild(childElementCNN);
childElementCNN .appendChild(document.createTextNode(strCNN));

Element childElementCTT = document.createElement("CTTREFF");//Child Node
rootElement.appendChild(childElementCTT);
childElementCTT.appendChild(document.createTextNode(strCTT));

TransformerFactory factory = TransformerFactory.newInstance();
Transformer transformer = factory.newTransformer();
Properties outFormat = new Properties();
outFormat.setProperty(OutputKeys.INDENT, "yes");
outFormat.setProperty(OutputKeys.METHOD, "xml");
outFormat.setProperty(OutputKeys.OMIT_XML_DECLARATION, "no");
outFormat.setProperty(OutputKeys.VERSION, "1.0");
outFormat.setProperty(OutputKeys.ENCODING, "UTF-8");
transformer.setOutputProperties(outFormat);
DOMSource domSource = new DOMSource(document.getDocumentElement());
OutputStream output = new ByteArrayOutputStream();
StreamResult result = new StreamResult(output);
transformer.transform(domSource, result);
String strInputXML = output.toString(); //Storing into a string

我想知道在android中构建XML，因为我想使用相同的函数来构建不同的XML。还有其他替代解决方案吗？如果有，请发表你的答案。

Answer 1

是的，请查看SimpleXML

您可以根据XML文档结构定义bean，并使用getters / setters来操作值。

@Root(name = "XMLINPUT")
class MyBean {

    @Element(name = "CNNREFF")
    private String child1;

    @Element(name = "CTTREFF")
    private String child2;


}

创建xml字符串的替代解决方案

1 个答案: