Question

我需要一点java的帮助。我需要在两点之间创建一些曲线。应用程序需要创建随机数量的曲线从随机生成的开始点连接到随机生成的终点。

到目前为止，这是我的代码：

/*
 * To change this template, choose Tools | Templates
 * and open the template in the editor.
 */
package tryproject;

import java.awt.Color;
import java.awt.Graphics;
import java.awt.Graphics2D;
import java.awt.Point;
import java.awt.RenderingHints;
import java.awt.geom.AffineTransform;
import java.awt.geom.QuadCurve2D;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Random;
import javax.swing.JPanel;

/**
 *
 * @author Q
 */
public class GUI extends JPanel{

    @Override

    protected void paintComponent(Graphics g) {
        super.paintComponent(g);


        ArrayList<Point> jaa = new ArrayList<Point>();
 Random ja = new Random();
Random p = new Random();
int x = ja.nextInt(50) +50;
int y = ja.nextInt(150) + 150;
Point pocetnaTacka = new Point(Math.abs(ja.nextInt(150)),Math.abs(ja.nextInt(150)));
Point zavrsmaTacka = new Point(Math.abs(ja.nextInt(300) ) ,Math.abs(ja.nextInt(300)));
int lx = pocetnaTacka.x;

int ly = pocetnaTacka.y; 
jaa.add(pocetnaTacka);
int rastojanje = (pocetnaTacka.x - zavrsmaTacka.x)/10;

for (int i = 1;i< Math.abs(ja.nextInt(8));i++){
        x =  lx + Math.abs(ja.nextInt(50));
        y =  ly + Math.abs(ja.nextInt(50));
         jaa.add(new Point(x,y));
        lx = x;
        ly = y;
     }

Graphics2D g2 = (Graphics2D) g;

    RenderingHints rh = new RenderingHints(
             RenderingHints.KEY_ANTIALIASING,
             RenderingHints.VALUE_ANTIALIAS_ON);
    g2.setRenderingHints(rh);
jaa.add(zavrsmaTacka);
Point lastpp = (Point)pocetnaTacka.clone();
for(Point pp: jaa)
{
    QuadCurve2D q = new QuadCurve2D.Float();
// draw QuadCurve2D.Float with set coordinates
q.setCurve(lastpp.x, lastpp.y, pp.x/3, pp.y/3, pp.x, pp.y);

  g2.draw(q);

    lastpp = (Point) pp.clone();

}
for(Point aa: jaa)
{
    System.out.println(aa.x + " , "+aa.y);
}

    } 



}

这应该是它应该看起来但我不能这样： http://www.dodaj.rs/f/2U/qT/4LubxcQN/everytime.png 每次应用程序运行时都会生成两个新点并将曲线转换为.. 我尝试过sin，cos函数，但我不能让它在两点之间工作。任何人都可以帮助我。

提前致谢。

Answer 1

我解决了这个问题。：

/*
 * To change this template, choose Tools | Templates
 * and open the template in the editor.
 */
package tryproject2;

import java.awt.Color;
import java.awt.Graphics;
import java.awt.Graphics2D;
import java.awt.Point;
import java.awt.RenderingHints;
import java.awt.geom.QuadCurve2D;
import java.util.ArrayList;
import java.util.Random;
import javax.swing.JPanel;

/**
 *
 * @author Q
 */
public class GUI extends JPanel {


    @Override
    protected void paintComponent(Graphics g) {
        super.paintComponent(g);
        Graphics2D g2 = (Graphics2D)g;
        ArrayList<Point> jaa = new ArrayList<Point>();
        Random pocetnaikrajnja = new Random();
              RenderingHints rh = new RenderingHints(
                      RenderingHints.KEY_ANTIALIASING,
             RenderingHints.VALUE_ANTIALIAS_ON);
        g2.setRenderingHints(rh);
        g2.setColor(Color.BLUE);
        Point pocetnaTacka = new Point(Math.abs(pocetnaikrajnja.nextInt(150)), Math.abs(pocetnaikrajnja.nextInt(200) + 100));
        g2.fillOval(pocetnaTacka.x,pocetnaTacka.y, 5, 5);


        jaa.add(pocetnaTacka);
        Point poslednjatacka = (Point) pocetnaTacka.clone();
        for (int i = 1;i< 6;i++){
            Point p = new Point(poslednjatacka.x + Math.abs(pocetnaikrajnja.nextInt(30) + 30),pocetnaTacka.y - Math.abs(pocetnaikrajnja.nextInt(30) + 30));
            poslednjatacka = p;
            jaa.add(p);
        }
         Point zavrsnaTacka  = null;

       zavrsnaTacka = new Point(jaa.get(jaa.size()-1).x+Math.abs(pocetnaikrajnja.nextInt(15) + 15),jaa.get(jaa.size()-1).y-70);


        jaa.add(zavrsnaTacka);
        g2.setColor(Color.RED);
        g2.fillOval(zavrsnaTacka.x,zavrsnaTacka.y, 5, 5);
        for(int i=0;i<jaa.size()-1;i++)
        {

               QuadCurve2D q = new QuadCurve2D.Float();
//if(i%2==0){
q.setCurve(jaa.get(i).x, jaa.get(i).y,jaa.get(i).x/1.2,jaa.get(i).y-Math.abs(pocetnaikrajnja.nextInt(35) + 35), jaa.get(i+1).x, jaa.get(i+1).y);
//}
//else
//{
  //  q.setCurve(jaa.get(i).x, jaa.get(i).y,jaa.get(i).x/1.2,jaa.get(i).y+Math.abs(pocetnaikrajnja.nextInt(35) + 35), jaa.get(i+1).x, jaa.get(i+1).y);

//}
  g2.draw(q);
}
        /**
         * Sakriven kod za grane.
        for(int i=1;i<jaa.size()-Math.abs(pocetnaikrajnja.nextInt(2)+1);i= i + Math.abs(pocetnaikrajnja.nextInt(5)))
        {
              QuadCurve2D q = new QuadCurve2D.Float();
              if(i%2==0)
                q.setCurve(jaa.get(i).x, jaa.get(i).y,jaa.get(i).x/1.2,jaa.get(i).y/1.2, jaa.get(i).x + Math.abs(pocetnaikrajnja.nextInt(5) + 7), jaa.get(i).y - Math.abs(pocetnaikrajnja.nextInt(10) + 60));
              else
                    q.setCurve(jaa.get(i).x, jaa.get(i).y,jaa.get(i).x/1.2,jaa.get(i).y/1.2, jaa.get(i).x + Math.abs(pocetnaikrajnja.nextInt(5) + 7), jaa.get(i).y + Math.abs(pocetnaikrajnja.nextInt(10) + 60));


              g2.draw(q);

        }
        */


    }
}

从点到点绘制随机线（也生成随机）

1 个答案: