Question

我正在尝试编写一个通过驱动器的脚本。该驱动器具有与此类似的文件夹结构：

| Folder 1
+--->Folder 1.txt
+--->Folder 1.nfo
| Folder 2
+--->Folder 2.doc
+--->Folder 2.nfo
+--->Folder 2.xls
| Folder 3
+--->Folder 3.txt
+--->Folder 3.nfo

较旧的我想要做的是读取目录中的每个文件，然后当我完成目录时，我想写一个日志到文本文件。我目前使用以下内容打开每个目录和文件：

logfile = open("log.txt")
for path, subdirs, files in os.walk(directory):
  txtfile = 0
  docfile = 0
  xlsfile = 0
  nfofile = 0
  for name in files:
    file = os.path.join(path, name)
    if file.endswith('.txt'):
      txtfile = 1
    elif file.endswith('.doc'):
      docfile = 1
    elif file.endswith('.xls'):
      xlsfile = 1
    elif file.endswith('.nfo'):
      nfofile = 1

    # if all files in a specific directory (Folder 1, Folder 2, etc) have been read, write line to log.txt

我只是不确定如何检查最后一个文件。该日志将用于查看目录中缺少的文件。任何有关这方面的帮助将不胜感激！

Answer 1

您可以列出目录中的所有文件:(取自here）

from os import listdir
from os.path import isfile, join
files = [ f for f in listdir(mypath) if isfile(join(mypath,f)) ]

然后检查您的文件：

if file == files[-1]: # do stuff

或者，您可以遍历files以简化操作，完成后，记录您的内容。我建议这样做。

Answer 2

看看是否有效：

import os
import os.path as opath


for path, dirs, files in os.walk(directory):
    exts = {}
    for fn, ext in (opath.splitext(f) for f in files):
        exts[ext] = exts.get(ext, 0) + 1

    with open(opath.join(path, "extlog.txt"), "w") as log:
        log.write("\n".join(("%s|%s" % (k, v)) for k, v in exts.items()) + "\n")

如何知道目录python中的最后一个文件

2 个答案: