如何根据不同对分组的列值选择行?

时间:2012-12-18 01:49:40

标签: c# sql linq

我的数据库中有以下信息:

 TO | FROM |    DATE   |  PRICE
AAA |  BBB | 12/3/2012 |  $100
AAA |  CCC | 12/3/2010 |  $200
AAA |  BBB | 10/3/2010 |  $450
BBB |  CCC | 09/7/2010 |  $270
BBB |  AAA | 06/9/2011 |  $130
AAA |  CCC | 12/3/2013 |  $176

我想编写一个查询(或者最好是LINQ表达式)来选择最新的TO-FROM对,所以基于上面的表我希望在我的查询中返回以下数据:

 TO | FROM |    DATE   |  PRICE
AAA |  BBB | 12/3/2012 |  $100
BBB |  CCC | 09/7/2010 |  $270
BBB |  AAA | 06/9/2011 |  $130
AAA |  CCC | 12/3/2013 |  $176

最好的方法是什么。

1 个答案:

答案 0 :(得分:0)

由于您尚未提及您的RDBMS,因此以下查询适用于大多数RDBMS

SELECT a.*
FROM    tableName a
        INNER JOIN
        (
            SELECT To, FROM, MAX(DATE) maxDate
            FROM tableName
            GROUP BY To, FROM
        ) b ON a.To = b.To AND
                a.FROM = b.FROM AND
                a.DATE = b.maxDATE

但如果你是RDBMS支持CTEWINDOWS FUNCTION

WITH latestRecord AS
(
SELECT [To], [FROM], DATE, Price,
        ROW_NUMBER() OVER (Partition BY [TO], [FROM] ORDER BY date DESC) rn
FROM tableName
)
SELECT [To], [FROM], DATE, Price
FROM latestRecord
WHERE rn = 1

WINDOWS FUNCTION ONLY

SELECT [To], [FROM], DATE, Price
FROM 
(
    SELECT [To], [FROM], DATE, Price,
            ROW_NUMBER() OVER (Partition BY [TO],[FROM] ORDER BY date DESC) rn
    FROM tableName
) s
WHERE rn = 1

还有一点需要注意,TOFROM有点保留关键字,必须使用转义字符进行转义,这取决于您使用的RDBMS