Question

(sql/with-connection {... mydatabase }
    (sql/with-query-results rows [ "select * from users where email in (?)" 
       [ "bob@site.com" "mary@other.com" ] ] 
       (doseq [rows row] 
            (prn row))))

这总是不会返回结果。我也尝试过使用“？”代替“（？）”

Answer 1

AFAIR你不能直接这样做。在场景宏with-query-results后面使用java.sql.PreparedStatement并为每个参数调用.setObject。所以你必须写这样的东西

(sql/with-connection db
  (sql/with-query-results rs
    [(str "select * from users where email in ("
          (apply
           str
           (interpose ", " (map #(str "\"" % "\"")
                                ["bob@site.com" "mary@other.com"]))) ")")]
    ...))

使用“in”参数生成已准备好的sql字符串："select * from users where email in (\"bob@site.com\", \"mary@other.com\")"。

更好的方法是使用一个像sqlkorma这样的clojure sql库。

Answer 2

现在，到2020年，至少在postgres中，您无需字符串即可进行连接。

像这样扩展ISQLParameter协议：

; This allows us to use clojure arrays as query parameters for JDBC.
; Thus, we don't need to do string concatenation to make IN clauses.
(extend-protocol clojure.java.jdbc/ISQLParameter
  Sequential
  ; Important: Sometimes you have to explicitly specify the type of array like ?::text[].
  (set-parameter [v ^PreparedStatement stmt ^long i]
    (let [conn (.getConnection stmt)
          meta (.getParameterMetaData stmt)
          type-name (.getParameterTypeName meta i)]
      (if-let [elem-type (when (= (first type-name) \_) (apply str (rest type-name)))]
        (.setObject stmt i (.createArrayOf conn elem-type (to-array v)))
        (.setObject stmt i v)))))

然后您可以运行

之类的查询

(jdbc/query db/db ["select 'banana' = ANY(?) as banana_included, 
                           'apple' = ANY(?) as apple_included" 
                   ["banana" "potato"] ["banana" "potato"]])

= ANY(array)语法与in子句的功能相同-据我所知，IN子句在postgres内部转换为= ANY(array)-不引用我的话。

如何使用clojure.jdbc查询列表

2 个答案: