Question

我目前有一个程序，其网格和线条将在网格中的点之间绘制。它使用标准绘图。我希望限制线条的长度，这样它们只能从相邻的点开始，但不知道我会怎么做。

由于

StdDraw.setCanvasSize(400, 400);
StdDraw.setXscale(0, 10);
StdDraw.setYscale(0, 10);      

//dots
double radius = .15;
double spacing = 2.0;

for (int i = 0; i <= 4; i++) {
    for (int j = 0; j <= 4; j++) {
        StdDraw.setPenColor(StdDraw.GRAY); 
        StdDraw.filledCircle(i * spacing, j * spacing, radius );
    }
}
StdDraw.setPenColor(StdDraw.BLUE); 
StdDraw.text(0, 9.5, player1_name);
StdDraw.setPenColor(StdDraw.RED); 
StdDraw.text(5, 9.5, player2_name);
int turn = 1;
     for (int i = 0; i <= 40; i++) { 
         if (turn % 2 == 0)
           StdDraw.setPenColor(StdDraw.RED);
         else
           StdDraw.setPenColor(StdDraw.BLUE);

         while(!StdDraw.mousePressed()) { }
         double x = StdDraw.mouseX();
         double y = StdDraw.mouseY();
   System.out.println(x + " " + y);
         StdDraw.setPenRadius(.01);
         StdDraw.show(200); 
               while(!StdDraw.mousePressed()) { }
               double x2 = StdDraw.mouseX();
               double y2 = StdDraw.mouseY();
               StdDraw.show(200); 
double xround = Math.round(x); 
double yround = Math.round(y);
double x2round = Math.round(x2);
double y2round = Math.round(y2);
  int xroundb = (int) xround; 
  int yroundb = (int) yround;
  int x2roundb = (int) x2round;
  int y2roundb = (int) y2round;
StdDraw.line(xround, yround, x2round, y2round);
System.out.println("Line Drawn"); 
StdDraw.show();

Answer 1

啊，我明白了。您没有询问实际正常工作的line方法，您希望逻辑使得如果未选择相邻点，则不会调用line。

嗯，首先我们需要知道允许哪些相邻连接。那我们可以有垂直吗？水平？对角线？我会解释每个以防万一

所以你有spacing = 2.0。那么，这应该足以检查邻接。

if (Math.abs(x2round - xround) > spacing) {
   // don't draw
} else if (Math.abs(y2round - yround) > spacing)) {
   // don't draw
} else if (Math.abs(y2round - yround) > 0.0) && Math.abs(x2round - xround) > 0.0) {
   // don't draw if diagonal connections are forbidden
   // if diagonal is allowed, remove this else if condition
} else {
   StdDraw.line(xround, yround, x2round, y2round);
}

因此，如果你不画画，那么你必须强制执行你的游戏逻辑。也许玩家会失去一个回合。也许玩家有另一次选择相邻点的机会。它是由你决定。由于舍入而比较双倍总是有点疯狂，因此您可能希望选择一个非常小的epsilon double值来确保捕获所有情况。而不是使用0.0。

限制标准绘制中的线条长度

1 个答案: