Question

我试图找出我尝试合并的表是否有identity列（来自php应用程序）。正在构建的查询是：

USE dhs;

select COLUMN_NAME as name 
from INFORMATION_SCHEMA.COLUMNS 
where TABLE_SCHEMA = 'dbo' 
and COLUMNPROPERTY(object_id(TABLE_NAME), COLUMN_NAME, 'IsIdentity') = 1 
AND TABLE_NAME = 'orders'

如果我在Management Studio中运行它，我会得到id的返回值（这是我所期望的）。但是，当我从我的应用程序运行相同的查询时，不会返回任何内容。我已经为我的数据库用户提供了完全权限，因此它不能成为权限问题。下面是我正在运行的php（当前返回false，即使它应该返回'id'）：

$array = empty($array) ? $_POST : $array; //if no array is passed, use post
        $info = self::information_schema($db, $schema, $table);
        $clean = array(); //the hex-exscaped key values pairs that are matched against the database column names (so only items whose key matches a column name are used)
        $primary = array();// ON section array
        $update = array(); //the array for elements to update, each position is set to target.$k = source.$k
        $insert = array(); //The insert string, which is essentially array_keys($clean) minus any identity field with source. prepended
        $fields = array(); //fields to insert to with no source. prepended and no identity fields included
        $query= "USE $db 
                                select COLUMN_NAME as name
                                from INFORMATION_SCHEMA.COLUMNS
                                where TABLE_SCHEMA = '$schema'
                                and COLUMNPROPERTY(object_id(TABLE_NAME), COLUMN_NAME, 'IsIdentity') = 1
                                AND TABLE_NAME = '$table'"; //this gets the identity column of table it has one (to prevent trying to insert into an IDENTITY field)
                    $handle = sqlsrv_query(self::$conn, $query);
        $value = sqlsrv_fetch_array($handle, SQLSRV_FETCH_NUMBERIC);
        var_dump($value);

SQL Server是否允许您从SSMS外部选择INFORMATION_SCHEMA？

检查标识列

0 个答案: