根据https://github.com/signal11/hidapi/issues/72 HIDAPI在Linux机器上应该是线程安全的。但是,我根本无法使用它。这就是我的工作:
#ifdef WIN32
#include <windows.h>
#endif
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <pthread.h>
#include <stdlib.h>
#include <assert.h>
#include "hidapi.h"
hid_device *handle;
static void *TaskCode(void *argument)
{
int res;
//hid_device *handle;
unsigned char buf[64];
// res = hid_init();
// if( res == -1 )
// {
// return (void*)1;
// }
//
// handle = hid_open(0x0911, 0x251c, NULL);
// if( handle == NULL )
// {
// return (void*)2;
// }
printf( "while 2\n");
while( 1 )
{
memset( buf, 64, 0 );
res = hid_read(handle, buf, 0);
if( res == -1 )
{
return (void*)3;
}
printf( "received %d bytes\n", res);
for (int i = 0; i < res; i++)
printf("Byte %d: %02x ", i+1, buf[i]);
//printf( "%02x ", buf[0]);
fflush(stdout);
}
return (void*)0;
}
int main(int argc, char* argv[])
{
int res;
//hid_device *handle;
unsigned char buf[65];
res = hid_init();
if( res == -1 )
{
return 1;
}
handle = hid_open(0x0911, 0x251c, NULL);
if( handle == NULL )
{
return 2;
}
hid_set_nonblocking( handle, 0 );
pthread_t thread;
int rc = pthread_create(&thread, NULL, TaskCode, NULL);
printf( "while 1\n");
while(1)
{
int a = getchar();
if( a == 'a')
{
// Get Device Type (cmd 0x82). The first byte is the report number (0x0).
buf[0] = 0x0;
buf[1] = 0x82;
res = hid_write(handle, buf, 65);
if( res != -1 )
printf( "write ok, transferred %d bytes\n", res );
else
{
printf( "write error\n" );
char* str = hid_error(handle);
printf( "error: %s\n", str );
return 1;
}
}
else if( a== 'b')
break;
}
void* trc;
rc = pthread_join(thread, &trc);
printf( "rc code: %d\n", (int)trc );
// Finalize the hidapi library
res = hid_exit();
return 0;
}
如果我不使用全局句柄,每次都会出现'写错误'。如果我这样做,就像在示例中一样,正式一切正常但hid_read总是返回0个字节......当然,如果我做简单的hid_write()后跟hid_read(),我会按预期得到对命令0x82的正确回复。我真的迷失在这里,我忽略了什么?
编辑:澄清,零字节也返回所有内容,包括。鼠标等上的按钮因此似乎可以工作,但数据缓冲区总是零字节。
答案 0 :(得分:1)
羞耻我,一个愚蠢的错误。代码应该是:
memset( buf, 0, 64 );
res = hid_read(handle, buf, 64);
然后它的工作原理。应该睡得更多,写得更少!