MySQLdb Python查询

Question

我正在尝试将PHP查询从PHP转换为MySQLdb for Python。

以下是PHP代码：

$query = "
        select
            `ip_address`.`address`,
            `interface`.`name`,
            `equipment`.`dns_hostname`,`interface`.`vrf_id`
        from
            `equipment` `equipment`
                inner join `tm_se_equipment` `tm_se_equipment`
                on `equipment`.`id` = `tm_se_equipment`.`equipment_id`
                    inner join `interface` `interface`
                    on `interface`.`equipment_id` = `equipment`.`id`
                        inner join `ip_address` `ip_address`
                        on `ip_address`.`if_id` = `interface`.`id`
        where
            (`ip_address`.`address` = '$ip_address') 
    ";

我试图像这样翻译但是没有用，我获取的唯一结果是()：

ip_address = ipaddr.IPAddress(linknet)
linknet = "1.1.1.1"

cursor.execute("""SELECT `ip_address`.`address`, `interface`.`name`, `equipment`.`dns_hostname`, `interface`.`vrf_id` FROM `equipment` `equipment` INNER JOIN `tm_se_equipment` `tm_se_equipment` ON `equipment`.`id` = `tm_se_equipment`.`equipment_id` INNER JOIN `interface` `interface` ON `interface`.`equipment_id` = `equipment`.`id` INNER JOIN `ip_address` `ip_address` ON `ip_address`.`if_id` = `interface`.`id` WHERE `ip_address`.`address` = %s""", (ip_address,))

Answer 1

试试这个：

cursor.execute("""SELECT `ip_address`.`address`, `interface`.`name`, `equipment`.`dns_hostname`, `interface`.`vrf_id` FROM `equipment` `equipment` INNER JOIN `tm_se_equipment` `tm_se_equipment` ON `equipment`.`id` = `tm_se_equipment`.`equipment_id` INNER JOIN `interface` `interface` ON `interface`.`equipment_id` = `equipment`.`id` INNER JOIN `ip_address` `ip_address` ON `ip_address`.`if_id` = `interface`.`id` WHERE `ip_address`.`address` = '%s'""" % ip_address)

或者，如果您尝试将ip地址作为执行函数的参数，则需要使用“？”而不是“％”