表

name varchar（35）
department varchar（50）
rating smallint（6）
easyiness smallint（6）
textbook varchar（3）
时间戳时间戳
course char（10）
曲线char（3）
评论文字

我使用下面这样的查询插入数据，它实际上并没有插入数据库，页面重新加载就是这样。这是print_r()和var_dump()的结果。实际查询功能如下。可能是什么问题？我认为它可以是某种类型的文本类型溢出。但我无法弄明白，谢谢你的帮助

print_r()结果：

insert into professor(name,department,rating,easiness,textbook,course,curve,comment)values('Cherry, Mark','HUMANITIES','8','8','yes','PHIL 3311','no','Go to class. He doesn't require it but it will make the difference between an A or a B. It's very difficult to do anything without being in class. He gives all the answers you need so long as you show up. He's a very good teacher and I would recommend him to someone else')

var_dump()结果：

string(424) "insert into professor(name,department,rating,easiness,textbook,course,curve,comment)values('Cherry, Mark','HUMANITIES','8','8','yes','PHIL 3311','no','Go to class. He doesn't require it but it will make the difference between an A or a B. It's very difficult to do anything without being in class. He gives all the answers you need so long as you show up. He's a very good teacher and I would recommend him to someone else')" bool(false)

这是我的代码：

function processadd()
{
    $name =htmlentities($_POST['prof']);
    $department =htmlentities($_POST['depart']);
    $rating =htmlentities($_POST['Rating']);
    $easy=htmlentities($_POST['Easiness']);
    $textbook =htmlentities($_POST['Book']);
    $course =htmlentities($_POST['course']);
    $curve =htmlentities($_POST['curve']);
    $comment =htmlentities($_POST['comment']);
    if($course == "" || $comment == "")
    {
        print"<div class=error><h3> Empty Fields exist!, please fill out completely</h3></div>";
    }
    else
    {
    $db = adodbConnect();
    $query = "insert into professor(name,department,rating,easiness,textbook,course,curve,comment)values('$name','$department','$rating','$easy','$textbook','$course','$curve','$comment')";
    $result = $db -> Execute($query);
    }
    print_r($query);
    print_r($result);
    print"<br>";
    print"<br>";
    print"<br>";
    var_dump($query);
    var_dump($result);

}

Answer 1

您的问题可能出现在评论中。看起来你并没有在整个评论中逃脱。尝试插入此声明：

insert into professor(name,department,rating,easiness,textbook,course,curve,comment)
values('Cherry, Mark','HUMANITIES','8','8','yes','PHIL 3311','no','Go to class. He doesn\'t require it but it will make the difference between an A or a B. It\'s very difficult to do anything without being in class. He gives all the answers you need so long as you show up. He\'s a very good teacher and I would recommend him to someone else');

Answer 2

虽然您没有指定您收到的错误，但我猜测它与您的查询中的引号无关，特别是（但不限于）comment列

例如，样本中的列是：

去上课。他不需要它，但它会有所作为在A或B之间。没有存在就很难做任何事情在班上。只要你出现，他就会提供你需要的所有答案。他是一位非常好的老师，我会把他推荐给别人

此文本包含多个单引号，这将破坏您的SQL查询并给您一个错误。

您在每个列的输入上使用htmlentities，但这不会阻止SQL注入;并且，默认情况下，htmlentities也不会转换单引号。

我不知道您的数据库类正在实现什么MySQL库，但您可能想尝试使用库的转义函数。

例如，如果您使用较旧的mysql_功能，请为每个值使用mysql_real_escape_string()代替htmlentities()。另一方面，如果您使用的是更推荐的MySQLi或PDO类，请将您的查询转换为预备语句。

PHP查询到数据库失败？

表

2 个答案: