我是一个字符串替代品,它带有一些值,并且想知道是否可以跳过一个键并将其保留在那里,而不是用空格填充它?
s='%(name)s has a %(animal)s that is %(animal_age)s years old'
#skip the animal value
s = s % {'name': 'Dolly', 'animal': 'bird'}#, 'animal_age': 10}
print s
Dolly has a bird that is %(animal_age)s years old
答案 0 :(得分:2)
您可以在字符串中使用两个%%
来跳过字符串格式化。:
In [169]: s='%(name)s has a %(animal)s that is %%(animal_age)s years old'
In [170]: s % {'name': 'Dolly', 'animal': 'bird', 'animal_age': 10}
Out[170]: 'Dolly has a bird that is %(animal_age)s years old'
或使用string.format()
:
In [172]: s='{name} has a {animal} that is %(animal_age)s years old'
In [173]: dic = {'animal': 'bird', 'animal_age': 10, 'name': 'Dolly'}
In [174]: s.format(**dic)
Out[174]: 'Dolly has a bird that is %(animal_age)s years old'