Question

可能重复：
MySQL Query GROUP BY day / month / year

我的php时间戳（例如1307362819）存储在我的数据库的一列中。我想在数天，周和月内对计数（*）进行分组。

例如，我想知道每天，每周和每月有多少条目。

如何实现这一目标？

Answer 1

您可以从时间戳中减去日，周和月值，并对减去的值进行分组。

按日值分组：

select count(*) from table group by from_unixtime(timeStampColumn, '%Y%m%d')

按周值分组：

select count(*) from table group by from_unixtime(timeStampColumn, '%Y%m%u')

按月值分组：

select count(*) from table group by from_unixtime(timeStampColumn, '%Y%m')

有关详细信息，请查看此页面：http://dev.mysql.com/doc/refman/5.0/en/date-and-time-functions.html

Answer 2

为什么不使用这些：＆lt;＆gt;

SELECT COUNT(*) FROM yourTable WHERE yourTimestampField > someTimestampAWeekPast;
SELECT COUNT(*) FROM yourTable WHERE yourTimestampField > someTimestampADayPast;

使用mysql日期/时间函数http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html计算过去的所需日期。如果将它们存储为int或string或其他任何内容，请使用UNIX_TIMESTAMP。

Answer 3

这里有一个很好的例子

to group by week

编辑：试试这个

          select
id_user,
year(time) as AYear, week(time) as AWeek, day(time) as Aday ,
count(week(time)) as TotalPerWeek , count(day(time)) as TotalPerDay ,
count(year(time)) as TotalPerYear
from yourtable
where id_user = 16             //// the user u want to check
group by id_user, AYear, AWeek , Aday
order by AYear, AWeek , Aday

Answer 4

SELECT MONTH( FROM_UNIXTIME(  `timeStamp` ) ) , COUNT(  `id` ) 
FROM  `discusComments` 
GROUP BY MONTH( FROM_UNIXTIME(  `timeStamp` ) )

MYSQL组按天，周和月使用php时间戳

4 个答案: