我正在开发一个JQuery脚本，它基本上根据输入从选择框中提取数据，并根据选择隐藏/显示变量（当前测试数据）
我让脚本工作到JQUERY刷新和更新值。我目前的问题是，我似乎无法通过其他步骤来传递变量。
这是我到目前为止所拥有的。现在我在将变量传递到下一步时遇到了问题。
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.6.1/jquery.min.js"></script>
<script type="text/javascript"><!--
$(document).ready(function() {
// When the form is submitted to PHP Call
$('#crs').submit(function() {
// Get form data ready for PHP Call
var Sphone = $('#crs #Sphone').val();
var Schat = $('#crs #Schat').val();
var Smeet = $('#crs #Smeet').val();
var Sremo = $('#crs #Sremo').val();
var Sport = $('#crs #Sport').val();
var Smail = $('#crs #Smail').val();
var Svoic = $('#crs #Svoic').val();
var Sfax = $('#crs #Sfax').val();
// put form data in a JSON format that will be sent to the PHP File
var data_json = {'Sphone':Sphone, 'Schat':Schat, 'Smeet':Smeet, 'Sremo':Sremo, 'Sport':Sport, 'Smail':Smail, 'Svoic':Svoic, 'Sfax':Sfax};
// Set AJAX method
// If succeeds, goes to the next step
$.ajax({
type: 'post',
url: 'script.php',
data: data_json,
beforeSend: function() {
// before send the request, displays a "Loading..." messaj in the element where the server response will be placed
$('#resp').html('Loading...');
},
timeout: 10000, // sets timeout for the request (10 seconds)
error: function(xhr, status, error) { alert('Error: '+ xhr.status+ ' - '+ error); },
success: function(response) { $('#resp').html(response); }
});
return false; // required to not open the page when form is submited
});
});
--></script>
</head>
<body>
<div id="resp"></div>
<h4>Fill the form:</h4>
<form action="script.php" method="post" id="crs">
Phone Support: <select name="Sphone" id="Sphone">
<option value="Pen1">Yes</option>
<option value="">No</option>
</select><br />
Live Chat Support: <select name="Schat" id="Schat">
<option value="Pen2">Yes</option>
<option value="">No</option>
</select><br />
Live Meeting: <select name="Smeet" id="Smeet">
<option value="Pen3">Yes</option>
<option value="">No</option>
</select><br />
Remote Support: <select name="Sremo" id="Sremo">
<option value="Pen3">Yes</option>
<option value="">No</option>
</select><br />
Ticket By Portal: <select name="Sport" id="Sport">
<option value="Pen3">Yes</option>
<option value="">No</option>
</select><br />
Ticket By Email: <select name="Smail" id="Smail">
<option value="Pen3">Yes</option>
<option value="">No</option>
</select><br />
Ticket By Voicemail: <select name="Svoic" id="Svoic">
<option value="Pen3">Yes</option>
<option value="">No</option>
</select><br />
Ticket By Fax: <select name="Sfax" id="Sfax">
<option value="Pen3">Yes</option>
<option value="">No</option>
</select><br />
<input type="submit" value="submit" />
</form>
if(isset($_POST['Sphone']) && isset($_POST['Schat']) && isset($_POST['Smeet']) && isset($_POST['Sremo']) && isset($_POST['Sport']) && isset($_POST['Smail']) && isset($_POST['Svoic']) && isset($_POST['Sfax'])) {
$_POST = array_map("strip_tags", $_POST); // Gets rid of tags in POST Call
// get data
$Sphone = $_POST['Sphone'];
$Schat = $_POST['Schat'];
$Smeet = $_POST['Smeet'];
$Sremo = $_POST['Sremo'];
$Sport = $_POST['Sport'];
$Smail = $_POST['Smail'];
$Svoic = $_POST['Svoic'];
$Sfax = $_POST['Sfax'];
// Define Full Output of variable
$arrow ='<textarea name="supportArticle" cols="160" rows="15" wrap="virtual">'.$Sphone.' <br> '.$Schat.' <br> '.$Smeet.' <br> '.$Sremo.' <br> '.$Sport.' <br> '.$Smail.' <br> '.$Svoic.' <br> '.$Sfax.'</textarea>';
function passVariable($arrow)
{
return $arrow or die(mysql_error());
}
}
echo $arrow;
我确实有更多代码，但这只是数据库连接等。
这可以很好地改变变量。现在我有笔1，笔2等...作为占位符（中间有间隔）。
我想将所有这些保存到一个文件中。我用一个名为$ arrow的变量对它进行了测试，它不会回显这个变量（也给它添加了一个DIE错误，然后删除了） - 任何接受者？