Question

以下是示例xml

<DOC>
<DOCNO>WSJ870323-0180</DOCNO>
<HL>Italy's Commercial Vehicle Sales</HL>
<DD>03/23/87</DD>
<DATELINE>TURIN, Italy</DATELINE>
<TEXT>Commercial-vehicle sales in Italy rose 11.4% in February from a year earlier, to 8,848 units, according to provisional figures from the Italian Association of Auto Makers.</TEXT>
</DOC>

<DOC>
<DOCNO>WSJ870323-0180</DOCNO>
<HL>Italy's Commercial Vehicle Sales</HL>
<DD>03/23/87</DD>
<DATELINE>TURIN, Italy</DATELINE>
<TEXT>Commercial-vehicle sales in Italy rose 11.4% in February from a year earlier, to 8,848 units, according to provisional figures from the Italian Association of Auto Makers.</TEXT>
</DOC>

以下代码无法解决原因？

       System.Xml.XmlDocument doc = new System.Xml.XmlDocument();
    doc.Load("docs.xml");

    XmlNodeList elemList = doc.GetElementsByTagName("DOC");
    for (int i = 0; i < elemList.Count; i++)
    {
        string docno = elemList[i].Attributes["DOCNO"].ToString();
    }

C＃4.0 wpf

Answer 1

使用此代码，假设您有一个有效的根：

XmlNodeList elemList = doc.GetElementsByTagName("DOC");
for (int i = 0; i < elemList.Count; i++)
{
    var elements = elemList[i].SelectNodes("DOCNO");
    if (elements == null || elements.Count == 0) continue;
    var firstElement = elements.Item(0);
    var docno = firstElement.InnerText;
}

Answer 2

使用Linq To Xml解析Xml要容易得多。例如，

var xDoc = XDocument.Load("docs.xml");

var docs = xDoc.Descendants("DOC")
            .Select(x => new{
                DocNo = x.Element("DOCNO").Value,
                Text = x.Element("TEXT").Value
            })
            .ToList();

c＃GetElementsByTagName然后读取内部标签值如何

2 个答案: