我正在研究的程序的目的是通过模拟动态指针数组来创建一个“改进”默认整数数组数据类型的类。尝试删除指针和指针数组时,我一直遇到错误,其中“Windows已触发project4.exe中的断点。”
这可能是由于堆的损坏,这表示project4.exe或它已加载的任何DLL中存在错误。
这也可能是由于用户在project4.exe具有焦点时按下F12。
输出窗口可能包含更多诊断信息。“
class Array
{
private:
int length;
int* data;
public:
Array();
Array(const Array &cpy);
~Array();
bool addint(int toadd);
bool deletelast();
int getlength();
friend ostream& operator<<(ostream &out, const Array &n);
};
ostream& operator<<(ostream &out, const Array &n);
Array::Array()
{
length = -1;
data = NULL;
}
Array::Array(const Array &cpy)
{
length = cpy.length; //value of length is copied
if (length < 0)
data = NULL;
else
{
data = new int [length];
for (int i=0; i<=length; i++)
data[i] = cpy.data[i];
}
}
Array::~Array()
{
if (length != 0)
delete [] data;
else
delete data;
data = NULL;
}
bool Array::addint(int toadd)
{
length ++;
int* point = new int[length];
for (int i=0; i < length; i++)
point[i] = data[i];
point[length] = toadd;
if (length != 0)
delete [] data;
data = point;
point = NULL;
return true;
}
bool Array::deletelast()
{
int* temppoint;
if (length > 0)
temppoint = new int [length-1];
else
temppoint = new int[0];
for (int i=0; i<length; i++)
temppoint[i] = data[i];
if (length == 0)
temppoint[0] = 0;
length --;
delete [] data;
data = temppoint;
temppoint = NULL;
return true;
}
void menu(Array var)
{
int selection=0,
input;
bool success;
Array* arrcpy;
while (selection != 3)
{
if (var.getlength() == -1)
{
cout << "What would you like to demonstrate?" << endl << "1) Add an integer " << endl
<< "2) Exit" << endl << "Enter your selection: ";
cin >> selection;
if (selection == 2)
selection = 4;
}
else
{
cout << endl << "Now what would you like to demonstrate?" << endl << "1) Add an integer " << endl
<< "2) Delete the last entered integer" << endl << "3) Copy constructor" << endl << "4) Exit" << endl << "Enter your selection: ";
cin >> selection;
}
if (selection==1)
{
cout << endl << "The length of the array before adding a new value is: " << var.getlength() + 1 << endl;
cout << "Please enter the integer that you wish to add: ";
cin >> input;
success = var.addint(input);
if (success)
cout << endl << "The data input was a success!" << endl << "The length of the array is now: "
<< var.getlength() + 1 << endl << "The new value of the array is: " << var << endl;
else
cout << endl << "The input failed" << endl;
}
if (selection == 2)
{
cout << endl << "The lenght of the array before the deletion is: " << var.getlength() + 1 << endl
<< "and the value held in the array is: " << var << endl;
success = var.deletelast();
if (success)
cout << endl << "The data deletion was a success!" << endl << "The length of the array is now: "
<< var.getlength() + 1 << endl << "The new value of the array is: " << var << endl;
else
cout << endl << "The deletion failed" << endl;
}
if (selection == 3)
{
cout << endl << "The lenght of the array being copied is: " << var.getlength() + 1 << endl
<< "and the value held in the array is: " << var << endl;
arrcpy=new Array(var);
cout << endl << "The length of the copied array is: " << arrcpy->getlength() +1 << endl
<< "and the value contained in the array is: " << *arrcpy;
delete arrcpy;
}
}
}
这就是我所遇到的所有相关源代码。接下来,delete
运算符和delete []
运算符的每个实例都导致了这个断点错误,我不确定我做错了什么。
编辑:重写代码使得length的值默认为0而不是-1,现在一切正常!
答案 0 :(得分:2)
我相信复制构造函数中的for (int i=0; i<=length; i++)
应该包含i<length
(小于,不小于或等于)。这是一个明显的问题。
此外,您正在传递addint()
方法中的边界。数组中的最后一个元素是索引[length-1]。
答案 1 :(得分:0)
int* point = new int[length];
由于您的长度从-1开始,因此该行的第一次调用将是new int[0]
。可能是问题..如果你坚持不修复length
的语义,你想在这里length+1
无关联,你应该看看std::vector
是如何做到的,而不是重新分配每一个添加,你应该尝试进行全面定位,只有在空间被填满时才重新分配。
答案 2 :(得分:0)
我了解这是一个老话题,我承认我没有阅读所有评论,但是关于为什么当长度更改为0时它似乎起作用的话题,我相信这可能是由于提供了nullptr到由无效大小组成的数组,然后再尝试删除此类指针将导致断点。