我想使用pexpect从python中使用maxima,每当maxima启动它会打印出一堆这种形式的东西:
$ maxima
Maxima 5.27.0 http://maxima.sourceforge.net
using Lisp SBCL 1.0.57-1.fc17
Distributed under the GNU Public License. See the file COPYING.
Dedicated to the memory of William Schelter.
The function bug_report() provides bug reporting information.
(%i1)
我想像这样启动pexpect:
import pexpect
cmd = 'maxima'
child = pexpect.spawn(cmd)
child.expect (' match all that stuff up to and including (%i1)')
child.sendline ('integrate(sin(x),x)')
chil.expect( match (%i2) i think ; see below sample session )
print child.before
如何匹配起始横幅到提示符(%i1)? 依此类推,当会话进行时,最大值也会将(%i1)的值递增1,
(%i1) integrate(sin(x),x);
(%o1) - cos(x)
(%i2) integrate(log(x),x);
(%o2) x log(x) - x
(%i3)
所以接下来的期望是:
child.expect ('match (%i2)')
child.sendline ('integrate(log(x),x)')
child.expect( match (%i3) )
print child.before
我如何匹配(递增)整数? 基本上我需要在打印(%o#)时匹配(%i#)。
答案 0 :(得分:1)
此正则表达式匹配它:\(%i\d\)
。如果您需要匹配(%o#)
,只需将i
替换为针中的o
。