Question

我想使用pexpect从python中使用maxima，每当maxima启动它会打印出一堆这种形式的东西：

$ maxima
Maxima 5.27.0 http://maxima.sourceforge.net
using Lisp SBCL 1.0.57-1.fc17
Distributed under the GNU Public License. See the file COPYING.
Dedicated to the memory of William Schelter.
The function bug_report() provides bug reporting information.
(%i1)

我想像这样启动pexpect：

import pexpect 
cmd = 'maxima'
child = pexpect.spawn(cmd)
child.expect (' match all that stuff up to and including (%i1)')
child.sendline ('integrate(sin(x),x)')
chil.expect( match (%i2) i think ; see below sample session  ) 
print child.before

如何匹配起始横幅到提示符（％i1）？依此类推，当会话进行时，最大值也会将（％i1）的值递增1，

(%i1) integrate(sin(x),x);
(%o1)                              - cos(x)
(%i2) integrate(log(x),x);
(%o2)                            x log(x) - x
(%i3)

所以接下来的期望是：

child.expect ('match (%i2)')
child.sendline ('integrate(log(x),x)')
child.expect( match (%i3) ) 
print child.before

我如何匹配（递增）整数？基本上我需要在打印（％o＃）时匹配（％i＃）。

Answer 1

此正则表达式匹配它：\(%i\d\)。如果您需要匹配(%o#)，只需将i替换为针中的o。

如何在python pexpect中匹配像（％i1）这样的正则表达式

1 个答案: