我有一个线程,我在其中捕获异常。我想要的是,当这种情况发生时,线程关闭/退出/死亡或我应该说什么,并显示一个警告对话框(不喜欢祝酒!)。
这是我的代码:
t1 = new Thread(new Runnable()
{
public void run()
{
Looper.prepare();
StringBuffer stringBuffer = new StringBuffer("");
BufferedReader bufferedReader = null;
URI uri = null;
try
{
requestAndMakeSheet(stringBuffer, bufferedReader, uri);
}
catch (Exception e)
{
//Toast.makeText(getBaseContext(), "Web Request Error", Toast.LENGTH_LONG).show();
//Log.e("Web Request Error", e.getMessage());
t1.interrupt();
AlertDialog.Builder parsingErrorBox = new AlertDialog.Builder(ReservationInfo.this);
parsingErrorBox.setTitle("Login error");
parsingErrorBox.setMessage("You may have to check your credentials and then try again.");
parsingErrorBox.show();
}
finally
{
if (bufferedReader!=null)
{
try
{
bufferedReader.close();
}
catch (IOException ioe)
{
Log.e("Web Request Error", ioe.getMessage());
}
}
}
}
});
t1.start();
try
{
t1.join();
mWebview.loadUrl("file:///"+Environment.getExternalStorageDirectory()+"/MySheet.html");
setContentView(mWebview);
}
catch (InterruptedException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
}
//End of le thread
}
此代码崩溃,我认为它与t1.interrupt有关(尝试停止,但也没有工作)。
如何修复此代码? 提前谢谢。
答案 0 :(得分:0)
为什么你还有t1.interrupt()?似乎你的线程将被终止,无论如何将它放在那里是什么原因?