我正在尝试用C编写一个程序,将捕获的 Raw 16kHz PCM 16位文件转换为 16位WAV 。
我看了一些帖子,推荐使用libsox
的人。安装它,现在我真的很难理解man-page。
到目前为止(通过阅读源码中的示例)我已经发现structs
:
可能用于描述我正在输入的数据。如果有必要,我也知道我正在处理多少信息(时间)?
赞赏一些指导!
答案 0 :(得分:4)
嗯,问题得到解答后,问题就解决了。但是我会在这里发布代码,以便人们可以分析它或者只是在他们自己的项目中使用它。
" simonc"提供的链接和" Nickolay O。"被使用了。在网上搜索有关各个字段的更多信息。
struct wavfile
{
char id[4]; // should always contain "RIFF"
int totallength; // total file length minus 8
char wavefmt[8]; // should be "WAVEfmt "
int format; // 16 for PCM format
short pcm; // 1 for PCM format
short channels; // channels
int frequency; // sampling frequency, 16000 in this case
int bytes_per_second;
short bytes_by_capture;
short bits_per_sample;
char data[4]; // should always contain "data"
int bytes_in_data;
};
//Writes a header to a file that has been opened (take heed that the correct flags
//must've been used. Binary mode required, then you should choose whether you want to
//append or overwrite current file
void write_wav_header(char* name, int samples, int channels){
struct wavfile filler;
FILE *pFile;
strcpy(filler.id, "RIFF");
filler.totallength = (samples * channels) + sizeof(struct wavfile) - 8; //81956
strcpy(filler.wavefmt, "WAVEfmt ");
filler.format = 16;
filler.pcm = 1;
filler.channels = channels;
filler.frequency = 16000;
filler.bits_per_sample = 16;
filler.bytes_per_second = filler.channels * filler.frequency * filler.bits_per_sample/8;
filler.bytes_by_capture = filler.channels*filler.bits_per_sample/8;
filler.bytes_in_data = samples * filler.channels * filler.bits_per_sample/8;
strcpy(filler.data, "data");
pFile = fopen(name, "wb");
fwrite(&filler, 1, sizeof(filler), pFile);
fclose(pFile);
}
答案 1 :(得分:1)
我建议手动编写WAV标题和数据,这对PCM来说非常简单:https://ccrma.stanford.edu/courses/422/projects/WaveFormat/