Question

是否可以将表达式用作sum:表达式的参数？

我的实体（NSManagedObject类）Drink包含属性costPerDrink，numberOfDrinks和drinkingDate。

我希望在一段时间内得到总费用（numberOfDrinks乘以costPerDrink）的总和。虽然我在单个属性上获得总和没有问题（例如，在时间段内numberOfDrinks的总和），但当我尝试在另一个（乘法）表达式上使用sum表达式时，我得到了错误：

NSInvalidArgumentException, reason: Unsupported argument to sum : 
(
    "costPerDrink * numberOfDrinks" 
)

参见代码：

// Init fech
NSFetchRequest *request = [[NSFetchRequest alloc] init];
NSEntityDescription *entity = [NSEntityDescription entityForName:@"Drink" inManagedObjectContext:[Service appContext]];
[request setEntity:entity];

// Return dictionary
[request setResultType:NSDictionaryResultType];

// Set conditions
[request setPredicate:[NSPredicate predicateWithFormat:@"(drinkingDate>=%@) AND (drinkingDate<=%@)", self.startDate, self.endDate]];

// Set 1st column to be returned - count of drinks
NSExpression *drinksExpression = [NSExpression expressionForKeyPath:@"numberOfDrinks"];
NSExpression *sumDrinksExpression = [NSExpression expressionForFunction:@"sum:" arguments:[NSArray arrayWithObject:drinksExpression]];
NSExpressionDescription *sumDrinksResultDescription = [[NSExpressionDescription alloc] init];
[sumDrinksResultDescription setName:@"sumDrinks"];
[sumDrinksResultDescription setExpression:sumDrinksExpression];
[sumDrinksResultDescription setExpressionResultType:NSInteger32AttributeType];

// Set 2nd column to be returned - total cost
NSExpression *costExpression = [NSExpression expressionForKeyPath:@"costPerDrink"];
NSExpression *totalExpression = [NSExpression expressionForFunction:@"multiply:by:"
                                                            arguments:[NSArray arrayWithObjects:costExpression,
                                                                                          drinksExpression, nil]];
NSExpression *sumCostExpression = [NSExpression expressionForFunction:@"sum:" arguments:[NSArray arrayWithObject:totalExpression]];
NSExpressionDescription *sumCostResultDescription = [[NSExpressionDescription alloc] init];
[sumCostResultDescription setName:@"sumCost"];
[sumCostResultDescription setExpression:sumCostExpression];
[sumCostResultDescription setExpressionResultType:NSDecimalAttributeType];

// Add expressions to fetch
[request setPropertiesToFetch:[NSArray arrayWithObjects: sumDrinksResultDescription, sumCostResultDescription, nil]];

// Execute fech
NSError *error;
NSArray *result = [[Service appContext] executeFetchRequest:request error:&error];

我完全理解，可以通过向totalCost实体添加自动计算的Drink属性，然后在没有sum:表达式的提取中使用multiply:by:来解决特定问题，但问题仍然存在 - 是否可以将表达式用作sum:表达式的参数？

使用另一个表达式作为sum：expression的参数从NSManagedObject获取聚合数据

0 个答案: