如何在python中的一个块中编写多个try语句?

时间:2012-12-14 07:52:41

标签: python exception exception-handling

我想这样做:

try:
    do()
except:
    do2()
except:
    do3()
except:
    do4()

如果do()失败,请执行do2(),如果do2()也失败,则执行do3()等等。

最好的问候

6 个答案:

答案 0 :(得分:22)

如果你真的不关心异常,你可以循环遍历案例,直到你成功:

for fn in (do, do2, do3, do4):
    try:
        fn()
        break
    except:
        continue

这至少避免了每个案例都必须缩进一次。如果不同的函数需要不同的参数,你可以使用functools.partial在循环之前“填充”它们。

答案 1 :(得分:9)

我会为此编写一个快速包装函数first()

用法value = first([f1, f2, f3, ..., fn], default='All failed')

#!/usr/bin/env


def first(flist, default=None):

    """ Try each function in `flist` until one does not throw an exception, and
    return the return value of that function. If all functions throw exceptions,
    return `default` 

    Args: 
        flist - list of functions to try
        default - value to return if all functions fail

    Returns:
        return value of first function that does not throw exception, or
        `default` if all throw exceptions.

    TODO: Also accept a list of (f, (exceptions)) tuples, where f is the
    function as above and (exceptions) is a tuple of exceptions that f should
    expect. This allows you to still re-raise unexpected exceptions.
    """

    for f in flist:
        try:
            return f()
        except:
            continue
    else:
        return default

# Testing.

def f():
    raise TypeError

def g():
    raise IndexError

def h():
    return 1


# We skip two exception-throwing functions and return value of the last.
assert first([f, g, h]) == 1

assert first([f, g, f], default='monty') == 'monty'

答案 2 :(得分:5)

这似乎是一件非常奇怪的事情,但我可能会在没有异常的情况下循环使用函数并突破:

for func in [do, do2, do3]:
    try:
        func()
    except Exception:
        pass
    else:
        break 

答案 3 :(得分:0)

您应该指定每次尝试捕获的异常类型。

try:
    do()
except TypeError: #for example first one - TypeError
    do_2()
except KeyError: #for example second one - KeyError
    do_3()

等等。

答案 4 :(得分:0)

这是我找到的最简单的方法,只是将尝试嵌入上一个除外。

try:
    do()
except:
    try:
        do2()
    except:
        do3()

答案 5 :(得分:-2)

import sys

try:
    f = open('myfile.txt')
    s = f.readline()
    i = int(s.strip())
except OSError as err:
    print("OS error: {0}".format(err))
except ValueError:
    print("Could not convert data to an integer.")
except:
    print("Unexpected error:", sys.exc_info()[0])
    raise