我想这样做:
try:
do()
except:
do2()
except:
do3()
except:
do4()
如果do()失败,请执行do2(),如果do2()也失败,则执行do3()等等。
最好的问候
答案 0 :(得分:22)
如果你真的不关心异常,你可以循环遍历案例,直到你成功:
for fn in (do, do2, do3, do4):
try:
fn()
break
except:
continue
这至少避免了每个案例都必须缩进一次。如果不同的函数需要不同的参数,你可以使用functools.partial在循环之前“填充”它们。
答案 1 :(得分:9)
我会为此编写一个快速包装函数first()
。
用法:value = first([f1, f2, f3, ..., fn], default='All failed')
#!/usr/bin/env
def first(flist, default=None):
""" Try each function in `flist` until one does not throw an exception, and
return the return value of that function. If all functions throw exceptions,
return `default`
Args:
flist - list of functions to try
default - value to return if all functions fail
Returns:
return value of first function that does not throw exception, or
`default` if all throw exceptions.
TODO: Also accept a list of (f, (exceptions)) tuples, where f is the
function as above and (exceptions) is a tuple of exceptions that f should
expect. This allows you to still re-raise unexpected exceptions.
"""
for f in flist:
try:
return f()
except:
continue
else:
return default
# Testing.
def f():
raise TypeError
def g():
raise IndexError
def h():
return 1
# We skip two exception-throwing functions and return value of the last.
assert first([f, g, h]) == 1
assert first([f, g, f], default='monty') == 'monty'
答案 2 :(得分:5)
这似乎是一件非常奇怪的事情,但我可能会在没有异常的情况下循环使用函数并突破:
for func in [do, do2, do3]:
try:
func()
except Exception:
pass
else:
break
答案 3 :(得分:0)
您应该指定每次尝试捕获的异常类型。
try:
do()
except TypeError: #for example first one - TypeError
do_2()
except KeyError: #for example second one - KeyError
do_3()
等等。
答案 4 :(得分:0)
这是我找到的最简单的方法,只是将尝试嵌入上一个除外。
try:
do()
except:
try:
do2()
except:
do3()
答案 5 :(得分:-2)
import sys
try:
f = open('myfile.txt')
s = f.readline()
i = int(s.strip())
except OSError as err:
print("OS error: {0}".format(err))
except ValueError:
print("Could not convert data to an integer.")
except:
print("Unexpected error:", sys.exc_info()[0])
raise