我正在尝试在JavaFX
TableView
中显示每项任务的进度和状态。每个任务代表一行TableView
。
每个任务在单独的线程中执行。任务可能是 - 从服务器下载文件,将文件从一个帐户复制到另一个帐户等。线程可能需要很长时间才能完成任务。我的应用程序还控制在队列中执行操作的线程数。使用默认设置,它一次最多可以运行5个线程。
我的问题是 - 我的TableView
未显示更新后的状态和进度。我必须点击列标题才能刷新TableView
。如何使TableView更新aromatic?在后台,如果我运行一个在特定时间间隔后自动触发的线程,以刷新TableView
使我的UI冻结。
示例没有显示我在我的应用中做了什么,但我试图证明我面临的问题。运行程序时,您将看到TableView有两列1.名称和2.进度。在启动时,每行的名称将为“之前”,而您将看到进度条正在运行。我在更新单元格值时添加了1秒的延迟并停止了进度条。
import java.util.logging.Level;
import java.util.logging.Logger;
import javafx.application.Application;
import javafx.beans.property.DoubleProperty;
import javafx.beans.property.SimpleDoubleProperty;
import javafx.beans.property.SimpleStringProperty;
import javafx.beans.property.StringProperty;
import javafx.collections.ObservableList;
import javafx.scene.Scene;
import javafx.scene.control.*;
import javafx.scene.control.cell.ProgressBarTableCell;
import javafx.scene.control.cell.PropertyValueFactory;
import javafx.scene.layout.StackPane;
import javafx.scene.layout.StackPaneBuilder;
import javafx.stage.Stage;
public class UpdateTableView extends Application {
private TableView<Person> personTable = new TableView<>();
private TableColumn colName = new TableColumn<>("Name");
private TableColumn colProgressBar = new TableColumn("Progress Bar");
@Override
public void start(Stage primaryStage) {
showDialog(primaryStage);
colName.setCellValueFactory(new PropertyValueFactory("name"));
colProgressBar.setCellValueFactory(new PropertyValueFactory("progressBar")); // "name" here is for just to render the column
colProgressBar.setCellFactory(ProgressBarTableCell.forTableColumn());
personTable.getColumns().addAll(colName, colProgressBar);
for (int i = 0; i < 10; i++) {
Person person = new Person();
person.setProgressBar(-1.0);
person.setName("Before" + i);
personTable.getItems().add(person);
}
Thread threadAction1 = new Thread() {
public void run() {
try {
Thread.sleep(1000);
} catch (InterruptedException ex) {
Logger.getLogger(UpdateTableView.class.getName()).log(Level.SEVERE, null, ex);
}
ObservableList<Person> items = personTable.getItems();
for (int i = 0; i < items.size(); i++) {
Person person = items.get(i);
person.setName("After" + i);
person.setProgressBar(0.0);
}
}
};
threadAction1.start();
}
public void showDialog(Stage primaryStage) {
try {
StackPane root = StackPaneBuilder.create().children(personTable).build();
primaryStage.setScene(new Scene(root, 300, 250));
primaryStage.show();
} catch (Exception ex) {
System.out.println("Exception caught while showing dialog" + ex.getMessage());
}
}
public static class Person {
private StringProperty name;
public void setName(String name) {
this.name = new SimpleStringProperty(name);
}
private DoubleProperty progressBar;
private Person() {
}
public double getProgressBar() {
return progressBar.get();
}
public void setProgressBar(double surname) {
this.progressBar = new SimpleDoubleProperty(surname);
}
public Person(String name, double surname) {
this.name = new SimpleStringProperty(name);
this.progressBar = new SimpleDoubleProperty(surname);
}
public String getName() {
return name.get();
}
public StringProperty nameProperty() {
return name;
}
public DoubleProperty progressBarProperty() {
return progressBar;
}
}
public static void main(String[] args) {
launch(args);
}
}
答案 0 :(得分:4)
您必须更新Person
课程,如下所示:
public static class Person {
private StringProperty name;
private DoubleProperty progressBar;
private Person() {
name = new SimpleStringProperty();
progressBar = new SimpleDoubleProperty();
}
public Person(String name, double surname) {
this.name = new SimpleStringProperty(name);
this.progressBar = new SimpleDoubleProperty(surname);
}
public void setName(String name) {
this.name.set(name);
}
public double getProgressBar() {
return progressBar.get();
}
public void setProgressBar(double surname) {
this.progressBar.set(surname);
}
public String getName() {
return name.get();
}
public StringProperty nameProperty() {
return name;
}
public DoubleProperty progressBarProperty() {
return progressBar;
}
}
在setter
方法中,您正在创建name
&amp;的新对象每次progressbar
,以便TableView
没有获得更新。