XML通过xPath获取节点名称

Question

我有这个XML

<Parent>
 <Children>
  <child1>1</child1>
  <secondchild>2</secondchild>
  <child3>3</child3>
  <fourth>4</fourth>
 </Children>
</Parent>

使用xpath，我想让每个Children的节点名称最终得到：

• child1
• secondhild
• child3
• 第四

像Parent/Children/*[@name]之类的东西 ..没有瞄准任何属性，只有主子节点名称

Answer 1

也许这个：

<?php
$string = '<Parent>
 <Children>
  <child1>1</child1>
  <secondchild>2</secondchild>
  <child3>3</child3>
  <fourth>4</fourth>
 </Children>
</Parent>';

$xml = new SimpleXMLElement($string);

$children = $xml->xpath('/Parent/Children/*');

foreach ($children as $child){
    echo $child->getName() . "\n";
}

或

<?php
$string = '<Parent>
 <Children>
  <child1>1</child1>
  <secondchild>2</secondchild>
  <child3>3</child3>
  <fourth>4</fourth>
 </Children>
</Parent>';

$xml = new SimpleXMLElement($string);

$children = $xml->xpath('/Parent/Children/*');
$result = array();

foreach ($children as $child){
    $result[] = $child->getName();
}

print_r($result);

Answer 2

试试这个XPATH：

Parent/Children/*/name()

这会在结果节点上调用name（）函数。