Question

这是我遇到问题的函数的简化版本：

function example(&$form) {
     $name = $form->getName();

     foreach ($form as $sub) {
          if ($sub instanceof Form) {
               example($sub);
          }
          // need this to be the first entry of $name
          echo $name;
      }

 }

 example($this->form);

我需要一种方法来保留$name

的第一个条目的值

Answer 1

尝试在函数中添加另一个参数

function example(&$form, $firstFormName = null) {
    $name = $form->getName();

    if(is_null($firstFormName))
        $firstFormName = $name;

    foreach ($form as $sub) {
        if ($sub instanceof Form) {
           example($sub, $firstFormName);
        }
    }
    // need this to be the first entry of $name
    echo $name;
}

example($this->form);

Answer 2

只需将值作为参数传递

function example(&$form, $init_name = null) {
    $name = $form->getName();
    if (empty($init_name)) {
        $init_name = $name;
    }

     foreach ($form as $sub) {
          if ($sub instanceof Form) {
               example($sub, $init_name);
          }
          // current name
          echo $name;
          // initial name
          echo $init_name;
      }
}

Answer 3

这些方面的东西应该可以帮到你。

$first_name = "";
foreach ($form as $sub) {
   if ($first_name == "") {
      $first_name = $sub;
   }
// The rest of your for loop here...

使用递归时记住对象的第一个字符串

3 个答案: