Question

我的高级技术人员准备了一个观点。查看源脚本，我无法理解列label的存在位置，因为两个表都不包含该列。它是一个作为视图的一部分存在的列 - 在运行中吗？

select label labelName
, e.name
, e.country 
from entity e

源脚本：

SELECT e.entity_id
, se.screen_id
, s.country_code
,desc_trans translatedValue
, et.language_code
, cp.NAME name
FROM entity e 
LEFT OUTER JOIN CONTROL_PREFIX cp 
    ON e.CONTROL_PREFIX_CODE = cp.CONTROL_PREFIX_CODE
, entity_trans et
, screen s
, screen_entity se
WHERE e.entity_id = et.entity_id 
AND e.entity_id = se.entity_id 
AND se.screen_id = s.screen_id 
AND e.entity_type_code = 'LB'

UNION

SELECT e.entity_id
, se.screen_id
, s.country_code
, field_name labelName
, label labelText
, NULL translatedValue
, l.language_code
, cp.NAME name
FROM entity e 
LEFT OUTER JOIN CONTROL_PREFIX cp 
    ON e.CONTROL_PREFIX_CODE = cp.CONTROL_PREFIX_CODE
, language l
, screen s
, screen_entity se
WHERE l.language_code NOT IN
(
    SELECT et1.language_code
    FROM entity e1
    , entity_trans et1
    WHERE e1.entity_id = et1.entity_id 
    AND e1.entity_id = e.entity_id 
    AND e1.entity_type_code = 'LB'
) 
AND e.entity_type_code = 'LB' 
AND s.screen_id = se.screen_id 
AND e.entity_id = se.entity_id;

Answer 1

假设您发布的SQL是用于生成视图的SQL并且已完成

即

create view myView as
select label labelName
, e.name
, e.country 
from entity e

列Label位于表Entity上，但在myView视图中显示为LabelName。

如果entity是视图的名称，则需要提供该视图背后的来源。

SQL在视图中创建新列

1 个答案: