解决复杂的SQL查询

时间:2012-12-13 19:44:37

标签: sql oracle

我有以下数据库表APP_USERS

USER_NAME       OLD_STATUS       NEW_STATUS      STATUS_CHANGE_DATE
------------------------------------------------------------------------------
STEVE BALE      LOGGED_OUT       UNAVAILABLE     12/12/2012 5:04:24.736437 AM
STEVE BALE      UNAVAILABLE      AVAILABLE       12/12/2012 6:04:24.736437 AM
STEVE BALE      AVAILABLE        UNAVAILABLE     12/12/2012 7:31:08.591801 AM
STEVE BALE      UNAVAILABLE      AVAILABLE       12/12/2012 7:41:46.373138 AM
STEVE BALE      AVAILABLE        UNAVAILABLE     12/12/2012 8:30:21.218388 AM
STEVE BALE      UNAVAILABLE      AVAILABLE       12/12/2012 9:24:27.812461 AM
STEVE BALE      AVAILABLE        UNAVAILABLE     12/12/2012 10:44:52.724405 AM
STEVE BALE      UNAVAILABLE      LOGGED_OUT      12/12/2012 11:30:50.724405 AM

我必须显示每个状态的用户状态开始日期和时间以及结束日期和时间。

类似于用户UNAVAILABLE从12/12/2012 5:04:24.736437 AM到12/12/2012 6:04:24.736437 AM。

1 个答案:

答案 0 :(得分:3)

您只需要“下一个”记录,因为状态似乎正在发生变化。您可以使用主导功能执行此操作:

select user_name, new_status, status_change_date as StartTime,
       lead(status_change_date) over (partition by user_name order by status_change_date) as EndTime
from app_users