Question

我想根据某个标签从文件中读取提取信息。例如：

SCRIPT_NAME:mySimpleShell.sh

This is a simple shell. I would like to have this as
Description. I also want to create a txt file our of this.

SCRIPT_NAME:myComplexShell.sh

This is a complex shell. I would like to have this as
Description. I also want to create a txt file our of this.

因此，当我将此文件传递给我的shell脚本时，我的shell将逐行读取它当它到达SCRIPT_NAME时，它将其解压缩并保存在$ FILE_NAME中，然后开始编写带有$ FILE_NAME.txt名称的磁盘上文件的描述。直到它到达文件末尾才会这样做。如果有3个SCRIPT_NAME标记，则会创建3个描述文件。

感谢您提前帮助我：）

Answer 1

使用while循环读取行。使用正则表达式检查行是否有SCRIPT_NAME，如果是，则提取文件名。如下所示：

#! /bin/bash
while IFS= read -r line
do
    if [[ $line =~ SCRIPT_NAME:(.*$) ]]
    then
        FILENAME="${BASH_REMATCH[1]}"
        echo "Writing to $FILENAME.txt"
    else
        echo "$line" >> "$FILENAME.txt"
    fi
done < inputFile

Answer 2

#!/bin/sh

awk '/^SCRIPT_NAME:/ { split( $0, a, ":" ); name=a[2]; next }
    name { print > name ".txt" }' ${1?No input file specified}

使用bash逐行读取文件，提取一些数据。怎么样？

2 个答案: