Question

我有一个DataGrid，它有一个DataGridTemplateColumn，它使用DataGrid的ItemsSource绑定，但是在DataGridTemplateColumn的ComboBox中，我希望能够绑定到View的ViewModel而不是ItemsSource。

 <DataGrid ItemsSource="{Binding ModelValues, Mode=TwoWay, UpdateSourceTrigger=PropertyChanged}" >
      <DataGridTemplateColumn Header="myHeader" Width="200">
           <DataGridTemplateColumn.CellTemplate>
                <DataTemplate>
                     <ComboBox DisplayMemberPath="Value" SelectedValuePath="Key" IsEnabled="False"
                          SelectedValue="{Binding myID, Mode=TwoWay}"
                          ItemsSource="{Binding Path=myList, 
                          RelativeSource={RelativeSource FindAncestor, AncestorType={x:Type local:ViewModel}}}" />
                </DataTemplate>
           </DataGridTemplateColumn.CellTemplate>
           <DataGridTemplateColumn.CellEditingTemplate>
                <DataTemplate>
                     <ComboBox DisplayMemberPath="Value" SelectedValuePath="Key" IsEnabled="False"
                          SelectedValue="{Binding myID, Mode=TwoWay}"
                          ItemsSource="{Binding Path=myList, 
                          RelativeSource={RelativeSource FindAncestor, AncestorType={x:Type local:ViewModel}}}" />
                </DataTemplate>
           </DataGridTemplateColumn.CellEditingTemplate>
      </DataGridTemplateColumn>
 </DataGrid>

ViewModel具有ModelValues属性以及myList属性。 ModelValues用于ItemsSource的{{1}}，我想DataGrid用于myList ComboBox。

如何更改ItemsSource命令以使其正常工作？

Answer 1

绑定到网格的datacontext：

<DataGrid ItemsSource="{Binding ModelValues, Mode=TwoWay, UpdateSourceTrigger=PropertyChanged}" >
      <DataGridTemplateColumn Header="myHeader" Width="200">
           <DataGridTemplateColumn.CellTemplate>
                <DataTemplate>
                     <ComboBox DisplayMemberPath="Value" SelectedValuePath="Key" IsEnabled="False"
                          SelectedValue="{Binding myID, Mode=TwoWay}"
                          ItemsSource="{Binding Path=DataContext.myList, 
                          RelativeSource={RelativeSource FindAncestor, AncestorType={x:Type DataGrid}}}" />
                </DataTemplate>
           </DataGridTemplateColumn.CellTemplate>
           <DataGridTemplateColumn.CellEditingTemplate>
                <DataTemplate>
                     <ComboBox DisplayMemberPath="Value" SelectedValuePath="Key" IsEnabled="False"
                          SelectedValue="{Binding myID, Mode=TwoWay}"
                          ItemsSource="{Binding Path=DataContext.myList, 
                          RelativeSource={RelativeSource FindAncestor, AncestorType={x:Type DataGrid}}}" />
                </DataTemplate>
           </DataGridTemplateColumn.CellEditingTemplate>
      </DataGridTemplateColumn>
 </DataGrid>

如何使用RelativeSource Binding创建DataGrid绑定到Model和ViewModel？

1 个答案: