Question

我正在尝试使用下面的代码在数据库中创建一个tabe。但是，它不起作用，我无法弄清楚原因。

生成的错误是'UNIQUE KEY ID (ID)'上的语法错误，但根据我正在使用的教程（以及我能找到的文档），看起来没问题。

我还尝试了'UNIQUE ID (ID)'和'UNIQUE ID'，但我仍然遇到语法错误。

CREATE TABLE wp_offices (
    ID smallint(3) NOT NULL AUTO_INCREMENT,
    office_created_by smallint(3) DEFAULT "0",
    office_created_date datetime DEFAULT "0000-00-00 00:00:00" NOT NULL,
    office_last_edited_by smallint(3) DEFAULT "0",
    office_last_edited_date datetime DEFAULT "0000-00-00 00:00:00" NOT NULL,
    office_name tinytext COLLATE latin1_general_ci,
    address_1 tinytext COLLATE latin1_general_ci,
    address_2 tinytext COLLATE latin1_general_ci,
    town tinytext COLLATE latin1_general_ci,
    county tinytext COLLATE latin1_general_ci,
    postcode tinytext COLLATE latin1_general_ci,
    telephone tinytext COLLATE latin1_general_ci,
    fax tinytext COLLATE latin1_general_ci,
    dx tinytext COLLATE latin1_general_ci,
    email tinytext COLLATE latin1_general_ci,
    google_maps text(256) COLLATE latin1_general_ci
)
UNIQUE KEY ID (ID);

有人可以告诉我我做错了什么吗？感谢。

Answer 1

它应该在大括号内

google_maps text(256) COLLATE latin1_general_ci,
UNIQUE KEY ID (ID)
);

Answer 2

创建表格的代码将是

   CREATE TABLE wp_offices(
    ID SMALLINT( 3 ) NOT NULL AUTO_INCREMENT ,
    office_created_by SMALLINT( 3 ) DEFAULT "0",
    office_created_date DATETIME DEFAULT "0000-00-00 00:00:00" NOT NULL ,
    office_last_edited_by SMALLINT( 3 ) DEFAULT "0",
    office_last_edited_date DATETIME DEFAULT "0000-00-00 00:00:00" NOT NULL ,
    office_name TINYTEXT COLLATE latin1_general_ci,
    address_1 TINYTEXT COLLATE latin1_general_ci,
    address_2 TINYTEXT COLLATE latin1_general_ci,
    town TINYTEXT COLLATE latin1_general_ci,
    county TINYTEXT COLLATE latin1_general_ci,
    postcode TINYTEXT COLLATE latin1_general_ci,
    telephone TINYTEXT COLLATE latin1_general_ci,
    fax TINYTEXT COLLATE latin1_general_ci,
    dx TINYTEXT COLLATE latin1_general_ci,
    email TINYTEXT COLLATE latin1_general_ci,
    google_maps TEXT( 256 ) COLLATE latin1_general_ci,
    UNIQUE KEY ID( ID )
    );

创建表时UNIQUE KEY上的语法错误

2 个答案: