每当我尝试使用YouTube API通过直接上传来上传大型视频时。我得到一个OutOfMemory异常。有什么办法可以摆脱这个吗? YouTube API没有说明使用直接上传的视频大小限制。
我放弃了直接上传。现在我尝试了可恢复的上传方式。我的代码如下。
YouTubeRequest request;
YouTubeRequestSettings settings = new YouTubeRequestSettings("YouTube Upload", Client Key, "Username", "Password");
request = new YouTubeRequest(settings);
Video newVideo = new Video();
ResumableUploader m_ResumableUploader = null;
Authenticator YouTubeAuthenticator;
m_ResumableUploader = new ResumableUploader(256); //chunksize 256 kilobyte
m_ResumableUploader.AsyncOperationCompleted += new AsyncOperationCompletedEventHandler(m_ResumableUploader_AsyncOperationCompleted);
m_ResumableUploader.AsyncOperationProgress += new AsyncOperationProgressEventHandler(m_ResumableUploader_AsyncOperationProgress);
YouTubeAuthenticator = new ClientLoginAuthenticator("YouTubeUploader", ServiceNames.YouTube, "kjohnson@resoluteinnovations.com", "password");
//AtomLink link = new AtomLink("http://uploads.gdata.youtube.com/resumable/feeds/api/users/uploads");
//link.Rel = ResumableUploader.CreateMediaRelation;
//newVideo.YouTubeEntry.Links.Add(link);
System.IO.FileStream stream = new System.IO.FileStream(filePath, System.IO.FileMode.Open, System.IO.FileAccess.Read);
byte[] chunk = new byte[256000];int count = 1;
while (true) {
int index = 0;
while (index < chunk.Length) {
int bytesRead = stream.Read(chunk, index, chunk.Length - index);
if (bytesRead == 0) {
break;
}
index += bytesRead;
}
if (index != 0) { // Our previous chunk may have been the last one
newVideo.MediaSource = new MediaFileSource(new MemoryStream(chunk), filePath, "video/quicktime");
if (count == 1) {
m_ResumableUploader.InsertAsync(YouTubeAuthenticator, newVideo.YouTubeEntry, new MemoryStream(chunk));
count++;
}
else
m_ResumableUploader.ResumeAsync(YouTubeAuthenticator, new Uri("http://uploads.gdata.youtube.com/resumable/feeds/api/users/uploads"), "POST", new MemoryStream(chunk), "video/quicktime", new object());
}
if (index != chunk.Length) { // We didn't read a full chunk: we're done
break;
}
}
谁能告诉我有什么问题?我的2 GB视频无法上传。
答案 0 :(得分:5)
我收到403 Forbidden错误的原因是因为我没有传入:
上传代码中未使用/发送上述代码中的请求变量。因此,我正在进行未经授权的上传。
答案 1 :(得分:4)
您可能无法处置物品。确保所有一次性物品都在使用声明中。
例如,此代码会将一个大型zip文件上传到服务器:
try
{
using (Stream ftpStream = FTPRequest.GetRequestStream())
{
using (FileStream file = File.OpenRead(ImagesZipFile))
{
// set up variables we'll use to read the file
int length = 1024;
byte[] buffer = new byte[length];
int bytesRead = 0;
// write the file to the request stream
do
{
bytesRead = file.Read(buffer, 0, length);
ftpStream.Write(buffer, 0, bytesRead);
}
while (bytesRead != 0);
}
}
}
catch (Exception e)
{
// throw the exception
throw e;
}