PostgreSQL - DataError:类型为numeric的输入语法无效:“Product”

时间:2012-12-13 12:20:42

标签: sql postgresql

所以我不明白为什么会出现这个错误。是字段值“Product”数字?.. 我有UNION ALL查询,它使第一行显示其他行的总和。我的查询很长,所以我不会发布它(但如果有必要,我会发布它。)

首先,我将提供我的代码片段:

with w as (
SELECT
...
CASE x.variants WHEN x.variants THEN x.product || ' - ' || x.variants else x.product END as product
...

) 

SELECT 
...
'Product' as product,
...
UNION ALL
SELECT * FROM w

所以我使用product列在第一行显示为'Product'(因为我不需要在第一行的这个字段中计算。但是计算其他字段总数)

当我运行查询时,它会输出以下错误:

DataError: invalid input syntax for type numeric: "Product"
LINE 104: 'Product' as product,

编辑: PostgreSQL版本8.4

完整查询:

(
with w as (SELECT
min(fld2.id) AS id, -- note. Posted code is working now, but this select part was not
fld2.partner as partner, -- the same that is at the bottom (where different first line
fld2.product as product, -- is queried. So that gave error.
fld2.qty1 as qty1,
fld2.qty2 as qty2,
fld2.q1 as q1,
fld2.q2 as q2,
CASE WHEN (q1 >= q2 and q2 != 0) THEN ((q1-q2)/q2) * 100 WHEN (q1=0 or q2=0) THEN NULL WHEN (q2 > q1 and q1!=0) THEN ((q1/q2)-1)*100 END as percent_q,
fld2.price_q as price_q,
fld2.y1  as y1,
fld2.y2 as y2,
CASE WHEN (y1 >= y2 and y2 != 0) THEN ((y1-y2)/y2) * 100 WHEN (y1=0 or y2=0) THEN NULL WHEN (y2 > y1 and y1!=0) THEN ((y1/y2)-1)*100 END as percent_y,
fld2. price_y as price_y

FROM
(
SELECT 
min(x.id) AS id,
x.partner as partner,
--quarter as quarter,
CASE x.variants WHEN x.variants THEN x.product || ' - ' || x.variants else x.product END as product,
sum(case when (calcyear=DATE_PART('year',  now()) and x.quarter=3) then x.qty else 0 end) as qty1,
sum(case when (calcyear=DATE_PART('year',  now() - '1 year'::interval) and x.quarter=3) then x.qty else 0 end) as qty2,
sum(case when (calcyear=DATE_PART('year',  now()) and x.quarter=3) then price_unit else 0 end) as q1,
sum(case when (calcyear=DATE_PART('year',  now() - '1 year'::interval) and x.quarter=3) then price_unit else 0 end) as q2,
sum(case calcyear when  DATE_PART('year',  now()) then price_unit else 0 end) as y1,
sum(case calcyear when DATE_PART('year',  now() - '1 year'::interval) then price_unit else 0 end) as y2,
sum(case when (calcyear=DATE_PART('year',  now()) and x.quarter=3) then price_unit WHEN (calcyear=DATE_PART('year',  now() - '1 year'::interval)  and x.quarter=3) THEN -1*price_unit end) AS price_q,
sum(case when calcyear=DATE_PART('year',  now()) then price_unit ELSE -1*price_unit end) AS price_y
FROM (
  SELECT
    min(so.id) as id,
    DATE_PART('year',  so.date_order) AS calcyear,
    DATE_PART('quarter',  so.date_order) AS quarter,
   sol.price_unit as price_unit,
   rp.name as partner,
   pt.name as product,
   pp.variants as variants,
   sol.product_uom_qty as qty
FROM 
sale_order AS so 
INNER JOIN sale_order_line AS sol ON (sol.order_id = so.id)
INNER JOIN res_partner as rp ON (so.partner_id = rp.id)
INNER JOIN product_product as pp ON (sol.product_id=pp.id)
INNER JOIN product_template as pt ON (pp.product_tmpl_id=pt.id)
WHERE EXISTS(
SELECT * FROM  res_partner_category_rel rpcl
WHERE 
rpcl.partner_id=rp.id and rpcl.category_id=37
and (so.date_order >= date_trunc('year', now() - '1 year'::interval)::timestamp::date  and so.date_order <= date_trunc('year', now()+ '1 year'::interval)::timestamp::date-1 )
and rp.distributor=True and rp.active=True
and so.state != 'cancel'
)
GROUP BY
variants,
calcyear,
quarter,
price_unit,
partner,
product,
qty
) AS x
GROUP BY
 partner,
x.variants,
x.product
ORDER BY
  partner
)fld2
GROUP BY
partner,
q1,
q2,
y1,
y2,
qty1,
qty2,
product,
price_q,
price_y,
percent_q,
percent_y
ORDER BY 
partner
)
SELECT
1111 as id,
'Viso' as partner,
'Product' as product,
sum(uf.qty1) as qty1,
sum(uf.qty2) as qty2,
sum(uf.q1) as q1,
sum(uf.q2) as q2,
sum(CASE WHEN (uf.q1 >= uf.q2 and uf.q2 != 0) THEN ((uf.q1-uf.q2)/uf.q2) * 100 WHEN (uf.q1=0 or uf.q2=0) THEN NULL WHEN (uf.q2 > uf.q1 and uf.q1!=0) THEN ((uf.q1/uf.q2)-1)*100 END) as percent_q,
sum(uf.price_q) as price_q,
sum(uf.y1)  as y1,
sum(uf.y2) as y2,
sum(CASE WHEN (uf.y1 >= uf.y2 and uf.y2 != 0) THEN ((uf.y1-uf.y2)/uf.y2) * 100 WHEN (uf.y1=0 or uf.y2=0) THEN NULL WHEN (uf.y2 > uf.y1 and uf.y1!=0) THEN ((uf.y1/uf.y2)-1)*100 END) as percent_y,
sum(uf.price_y) as price_y
FROM 
(
SELECT 
sum(price_q) as price_q,
sum(price_y) as price_y,
sum(qty1) as qty1,
sum(qty2) as qty2,
sum(q1) as q1,
sum(q2) as q2,
sum(y1)  as y1,
sum(y2) as y2
FROM w
)uf
UNION ALL
SELECT * FROM w
) fld

1 个答案:

答案 0 :(得分:6)

好的我发现了什么问题。愚蠢的我:)。它给出了这个错误,因为查询的主要部分,选择列顺序是错误的(即使在我的系统中它是使用图形界面进行排序,但在这种情况下,当使用UNION ALL时,列也需要正确排序)。所以我改变了顺序,使其与第一行中的顺序相同,并且有效。