Question

我有一个与Sql Server 2005（Tsql）相关的问题

我有两列日期状态

数据看起来像......

Date                    Status

2012-09-01 00:01:00.000 2

2012-09-01 04:17:00.000 4

2012-09-01 04:34:00.000 4

2012-09-01 04:35:00.000 4

2012-09-01 04:35:48.000 4

2012-09-01 04:35:51.000 1

2012-09-01 17:28:25.000 2

2012-09-01 23:58:00.000 4

2012-09-01 23:59:00.000 1

我需要计算状态之间的时差......例如。最短的时间是什么时候状态2开始和最大时间当状态= 1（停止）在该日期之间我想要分钟数。我已经通过游标检查状态并记录变量中的最小时间和最长时间

我们是否可以轻松使用CTE。

我的查询需要很长时间才能完成......请帮助。

   DECLARE @pdunitid INT
        DECLARE @Date DATETIME
        DECLARE @pddatetime DATETIME
        DECLARE @pdstatus INT
        DECLARE @starttime DATETIME
        DECLARE @endTime DATETIME
        DECLARE @calc INT
        DECLARE @Totaltime INT
        DECLARE @START INT


        SET @pdunitid = 33568906
        SET @Date = GETDATE() - 102
        set @Totaltime = 0
        SET @calc = 0
        SET @START = 0


        DECLARE s CURSOR FAST_FORWARD FOR
        SELECT pddatetime,pdstatus FROM s1 WITH (NOLOCK)
        WHERE  pdunitid = @pdUnitid
        AND CONVERT(VARCHAR,pddatetime,112) = CONVERT(VARCHAR,@Date,112)
        ORDER BY pddatetime,pdstatus 

        OPEN s 

        FETCH NEXT FROM s INTO @pddatetime,@pdstatus
        WHILE @@FETCH_STATUS = 0 
            BEGIN
                -- status 2 is for start sometimes you don't get start so you will have to use the first date with status 4

                IF pdstatus IN (2,4)  AND @START = 0 
                    BEGIN 
                        SET @starttime = @pddatetime
                        SET @START = 1
                    END

                -- status 1 is for stop 

                IF (@pdstatus= 1) 
                    BEGIN 
                        SET @endTime = @pddatetime
                        SET @calc = 1   
                    END

                -- if you dont get the status 1 by '23:59:00' take the end time


            IF  convert(varchar,@pdgpsdatetime,108) = '23:59:00'
                    BEGIN 
                        SET @endTime = @pddatetime
                        SET @calc = 1   
            END

                -- Calculate the minutes.

                IF @calc = 1 
                    BEGIN 
                        SET @Totaltime = @Totaltime + DATEDIFF(mi, @starttime,@endTime)
                        SET @calc = 0   
                        SET @START = 0
                    END
        FETCH NEXT FROM s INTO @pddatetime,@pdstatus
            END
        CLOSE s
        DEALLOCATE s

        SELECT  @Totaltime

Answer 1

尝试此操作，而不是#tbl放置您的表名：

DROP TABLE #tbl
CREATE TABLE #tbl([Date] DATETIME, [Status] INT)
INSERT  #tbl
VALUES  
('2012-09-01 00:01:00.000',  2),
('2012-09-01 04:17:00.000',  4),
('2012-09-01 04:34:00.000',  4),
('2012-09-01 04:35:00.000',  4),
('2012-09-01 04:35:48.000',  4),
('2012-09-01 04:35:51.000',  1),
('2012-09-01 17:28:25.000',  2),
('2012-09-01 23:58:00.000',  4),
('2012-09-01 23:59:00.000',  1),

-- for 2012-09-05 there are no statuses 1 or 2
--('2012-09-05 00:01:00.000',  2),
('2012-09-05 04:17:00.000',  4),
('2012-09-05 04:34:00.000',  4),
('2012-09-05 04:35:00.000',  4),
('2012-09-05 04:35:48.000',  4),
('2012-09-05 04:35:51.000',  4),
('2012-09-05 17:28:25.000',  4),
('2012-09-05 23:58:00.000',  4)
--('2012-09-05 23:59:00.000',  1)

;WITH tbl AS 
(
    SELECT  *,
            ROW_NUMBER() OVER (ORDER BY [Date]) id
    FROM    #tbl
), 
b AS 
(
    SELECT  MIN([Date]) MinDate,
            MAX([Date]) MaxDate,
            CAST([Date] AS DATE) dateWithoutTime
    FROM    tbl
    GROUP   BY CAST([Date] AS DATE)
),
a AS
(
    SELECT  *,
            ROW_NUMBER() OVER (ORDER BY [Date]) num
    FROM    tbl
    LEFT JOIN 
            b ON 
            b.MaxDate = [Date]
    OR      b.MinDate = [Date]
    WHERE   [Status] IN (2, 1)
    OR      [Date] = CASE WHEN NOT EXISTS (SELECT 1 FROM #tbl c WHERE c.Status = 2 AND CAST(c.[Date] AS DATE) = b.dateWithoutTime) THEN b.MinDate END
    OR      [Date] = CASE WHEN NOT EXISTS (SELECT 1 FROM #tbl c WHERE c.Status = 1 AND CAST(c.[Date] AS DATE) = b.dateWithoutTime) THEN b.MaxDate END
)

SELECT  
        tbl.Date,
        tbl.Status,
        CASE WHEN a2.num % 2 = 0 THEN DATEDIFF(MINUTE, a1.Date, a2.Date) END Diff
FROM    tbl
LEFT JOIN   
        a a2 ON tbl.id = a2.id
LEFT JOIN   
        a a1 ON a2.num = a1.num + 1
ORDER BY [Date]

两个日期之间的分钟数取决于状态

1 个答案: