通过键数组设置ruby哈希元素值

时间:2012-12-13 09:23:55

标签: ruby hash

这是我得到的:

hash = {:a => {:b => [{:c => old_val}]}}
keys = [:a, :b, 0, :c]
new_val = 10

哈希结构和密钥集可以有所不同 我需要得到

hash[:a][:b][0][:c] == new_val

谢谢!

2 个答案:

答案 0 :(得分:6)

您可以使用inject遍历嵌套结构:

hash = {:a => {:b => [{:c => "foo"}]}}
keys = [:a, :b, 0, :c]

keys.inject(hash) {|structure, key| structure[key]}
# => "foo"

所以,你只需修改它就可以对最后一个键进行设置。也许像是

last_key = keys.pop
# => :c

nested_hash = keys.inject(hash) {|structure, key| structure[key]}
# => {:c => "foo"}

nested_hash[last_key] = "bar"

hash
# => {:a => {:b => [{:c => "bar"}]}}

答案 1 :(得分:3)

与Andy相似,但您可以使用Symbol#to_proc来缩短它。

hash = {:a => {:b => [{:c => :old_val}]}}
keys = [:a, :b, 0, :c]
new_val = 10
keys[0...-1].inject(hash, &:fetch)[keys.last] = new_val