Question

我创建了一个可扩展的列表视图，子视图有复选框，当展开父视图时，选中一个复选框，不仅要选中该复选框，还要检查另一个复选框。我不知道为什么以及如何解决这个问题。我在此链接中将源代码上传到mediafire.com：

http://www.mediafire.com/?eih80athr56ejg2

这是MainActivity.java

public class MainActivity extends Activity {

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    SetListView();
}

private void SetListView(){
    ExpandableListView lv=(ExpandableListView)findViewById(R.id.listview);
    ExpAdapter adapter=new ExpAdapter(this);
    lv.setAdapter(adapter);
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
    getMenuInflater().inflate(R.menu.activity_main, menu);
    return true;
}

这是ExpAdapter.java

public class ExpAdapter extends BaseExpandableListAdapter{
Context mContext;
int[][] data= new int[4][20];
public ExpAdapter(Context c){
    mContext=c;
}
@Override
public Object getChild(int arg0, int arg1) {
    // TODO Auto-generated method stub
    return null;
}

@Override
public long getChildId(int arg0, int arg1) {
    // TODO Auto-generated method stub
    return 0;
}

@Override
public View getChildView(int groupPosition, int childPosition, boolean arg2, View convertView,
        ViewGroup parent) {
    // TODO Auto-generated method stub
    if(convertView==null){
         LayoutInflater inflater =  (LayoutInflater) mContext.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
         convertView = inflater.inflate(R.layout.childview,parent, false);
    }
    TextView tv=(TextView)convertView.findViewById(R.id.txtChild);
    tv.setText("Child Position="+childPosition);
    return convertView;
}

@Override
public int getChildrenCount(int arg0) {
    // TODO Auto-generated method stub
    return data[arg0].length;
}

@Override
public Object getGroup(int arg0) {
    // TODO Auto-generated method stub
    return null;
}

@Override
public int getGroupCount() {
    // TODO Auto-generated method stub
    return data.length;
}

@Override
public long getGroupId(int arg0) {
    // TODO Auto-generated method stub
    return 0;
}

@Override
public View getGroupView(int groupPosition, boolean arg1, View convertView, ViewGroup parent) {
    // TODO Auto-generated method stub
    if(convertView==null){
         LayoutInflater inflater =  (LayoutInflater) mContext.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
         convertView = inflater.inflate(R.layout.groupview,parent, false);
    }
    TextView tv=(TextView)convertView.findViewById(R.id.txtGroup);
    tv.setText("Group Position="+groupPosition);
    return convertView;
}

@Override
public boolean hasStableIds() {
    // TODO Auto-generated method stub
    return false;
}

@Override
public boolean isChildSelectable(int arg0, int arg1) {
    // TODO Auto-generated method stub
    return false;
}

Answer 1

我已关注http://androidtrainningcenter.blogspot.in/2012/07/android-expandable-listview-simple.html

我们只需要存储您的复选框已检查状态即可。我在子视图中添加了一个复选框xml design＆amp;将其状态存储在NewAdapter中，以便在父视图扩展时我们可以恢复复选框状态。

在NewAdapter中完成的修改：

声明了一个名为selectedNames的String类型的列表。

更改了getChildView方法实现，如下所示。

tempChild = (ArrayList<String>) Childtem.get(groupPosition);
TextView text = null;

if (convertView == null) {
    convertView = minflater.inflate(R.layout.childrow, null);
}

text = (TextView) convertView.findViewById(R.id.textView1);
text.setText(tempChild.get(childPosition));

cb = (CheckBox) convertView.findViewById(R.id.cb_item);

cb.setOnCheckedChangeListener(null);

        cb.setChecked(false);

if (selectedNames.size() > 0
        && selectedNames.indexOf(tempChild.get(childPosition)) != -1) {

    cb.setChecked(true);
    // Log.d("Present",tempChild.get(childPosition));

} 

cb.setOnCheckedChangeListener(new OnCheckedChangeListener() {
    public void onCheckedChanged(CompoundButton buttonView,
            boolean isChecked) {
        if (isChecked) {

            int i = selectedNames.indexOf(tempChild.get(childPosition));

            if (i == -1) {
                selectedNames.add(tempChild.get(childPosition));
            }
        } else {

            int i = selectedNames.indexOf(tempChild.get(childPosition));

            if (i != -1) {
                selectedNames.remove(i);
            }

        }

    }
});

return convertView;

（Android需要帮助）Checkbox会自动在expandablelistview中疯狂检查

1 个答案: