Question

我正在尝试使这个jquery代码只重写父级ul li而不是ul li里面。

任何想法如何实现这一目标？

//This is for footer slider, it rewrites 1 ul into several uls that contain 4 li max.
    // get the container, useful for later too...
    var container = $(".fproductslides");

    // get all available UL and LI elements...
    // this doesn't order featured listings at the top of the list
    // var li_elements = container.find("LI").clone();
    // this does order featured listings at the top of the list
    var li_elements = container.find("LI.slidefeatured").clone();
    li_elements = li_elements.add(container.find('LI:not(.slidefeatured)').clone());

    // remove the current content so that we can rebuild it for the slider...
    container.find("UL").remove();

    // build the slider container...
    var slide_container = $("<div />");
    slide_container.addClass("slides_container");

    // tricky part: looping through the LI's and building each of the slides...
    // first create some helpful variables...
    var li_elements_per_slide = 3;
    var li_counter = 0;
    // create the first slide, with a UL to hold the LI's...
    var current_li_div = $("<div />");
    current_li_div.append($("<ul />"));

    // loop through the LI's...
    li_elements.each(function(index, element){

        li_counter++;
        var current_li = $(element).clone();
        current_li_div.find("UL").append(current_li);

        if (li_counter % li_elements_per_slide == 0)
        {
            // we've hit 4 in this list, so add the slide and make
            // a new one, using same code as before...
            container.append(current_li_div);
            current_li_div = $("<div />");
            current_li_div.append($("<ul />"));
        }

    });

    // we might have an uneven number of LI's, so we need to check for this...
    if (li_counter % li_elements_per_slide != 0)
        container.append(current_li_div);

Answer 1

您可以使用parent()方法获取父DOM元素。你也可以传递像ul.parent这样的选择器字符串来过滤父元素。

<ul class='parent'>
    <li class='child'></li>
</ul>

$('li.child').parent('ul.parent')

重写jquery，以便它只针对父ul li

1 个答案: