Question

Write1 [1.0]
Write1 [12.0]
Write1 ['C:/Users/san/Modeler/']
Write1 ['png']
Write1 ['rgb']
Write1 [True]
Write2 [1.0]
Write2 [1.0]
Write2 ['']
Write2 [' ']
Write2 ['rgb']
Write2 [False]

我想像这样制作词典 {'Write1'：[1.0,12.0，'c：/ path'，'png'，'rgb'，True]，'Write2'：[1.0,1.0，''，''，'rgb'，False]} 列表中的值来自nuke.toNode（wNode）[eachAttrib] .value（）这就是我试图做的事情

attributes=[]
wnodeData={}
for wNode in writeNodes:
    for eachAttrib in ['first','last','file','file_type','channels','use_limit']:
        wnodeData[wNode]=attributes
        attributes.append(nuke.toNode(wNode)[eachAttrib].value())

Answer 1

类似的东西：

text="""Write1 [1.0]
Write1 [12.0]
Write1 ['C:/Users/san/Modeler/']
Write1 ['png']
Write1 ['rgb']
Write1 [True]
Write2 [1.0]
Write2 [1.0]
Write2 ['']
Write2 [' ']
Write2 ['rgb']
Write2 [False]"""

from ast import literal_eval

d = {}
lines = text.splitlines()
for line in lines:
    k, v = line.split(' ', 1)
    val = literal_eval(v)[0]
    d.setdefault(k, []).append(val)

print d

# {'Write1': [1.0, 12.0, 'C:/Users/san/Modeler/', 'png', 'rgb', True], 'Write2': [1.0, 1.0, '', ' ', 'rgb', False]}

Answer 2

import collections

s = '''Write1 [1.0]
Write1 [12.0]
Write1 ['C:/Users/san/Modeler/']
Write1 ['png']
Write1 ['rgb']
Write1 [True]
Write2 [1.0]
Write2 [1.0]
Write2 ['']
Write2 [' ']
Write2 ['rgb']
Write2 [False]'''

d = collections.defaultdict(list)
for line in s.split('\n'):
    print(line)
    key, val = line.split(' ', 1)
    d[key].append(val[1:-1])
print(d)

显然，如果你有一个文本文件而不是一个字符串，你可以替换for循环，比如说：

with open('mystuff.txt', 'r') as f:
    for line in f:

如果你想实际评估括号内的值（所以你得到1.0而不是字符串'1.0'的浮点数，字符串'png'而不是字符串{{ 1}}等等，你需要知道他们写的语言并解析它。看起来它们是Python的一个子集，其中每个东西都是没有转义的单引号字符串文字，非指数格式的浮点文字或布尔文字，但我不会假设不知道价值来自哪里（我当然不会在不知道它们来自何处的情况下调用"'png'"，因为那时有人可以将eval粘贴在文本文件中，并且你会评估

Answer 3

write1 = {'write1':[1,2,3,4] }

应该有用......

Answer 4

使用默认值作为列表创建一个defaultdict，然后开始追加（或使用其他列表方法）。

如何将两个具有值的字典键作为列表

4 个答案: