Question

我正在寻找的是月份的日期，例如2,5,30或31.整数形式，而不是字符串。我不是在寻找一个有节目的日期，而是今天的日期，无论他们身处何地。

Answer 1

以上所有答案都是实现这一目标的不良方法。这是正确的方法：

NSDate *date = [NSDate date];
NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *components = [calendar components:NSDayCalendarUnit fromDate:date];
NSInteger day = components.day;

Answer 2

NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:@"d"];
NSInteger day = [[dateFormat stringFromDate:[NSDate date]] intValue];

Answer 3

从NSDate开始，然后通过NSDateFormatter运行。

https://developer.apple.com/library/mac/#documentation/Cocoa/Reference/Foundation/Classes/NSDate_Class/Reference/Reference.html

https://developer.apple.com/library/mac/#documentation/Cocoa/Reference/Foundation/Classes/NSDateFormatter_Class/Reference/Reference.html

Answer 4

这可能有用：

NSDate *theDate;

// Set theDate to the date you want
// For example, theDate = [NSDate date]; to get today's date

NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
formatter.dateFormat = @"d";
NSString *theDayString = [formatter stringFromDate:theDate];
int theDay = theDayString.intValue;

NSLog (@"%d", theDay);

theDay包含您正在寻找的价值！

如何以数字格式获取月份日期？

4 个答案: