我有一份作业,但我很难理解作业真正要求我做什么,或者如何去做。我知道复数是多少,但我不明白C ++和Python版本的以下操作应该做什么:
op: Complex × Complex → Complex
op: Complex × double → Complex
op: double × Complex → Complex
一倍?我不明白双重问题在哪里。另外python版本应该将复合体转换为字符串,我再也不明白它的要求。是说将字符串(整数?)字面转换为字符串数据类型?如果您可以尝试帮助我了解作业的要求,请告诉我,以便我可以尝试编程。
复数类
用C ++,Java和Python设计一个代表复杂的类 数字和支持重要的操作,如添加, 减法,乘法和除法。对于C ++和Python 您需要为每个版本实现以下功能 操作:
op: Complex × Complex → Complex op: Complex × double → Complex op: double × Complex → Complex
其中op是+, - ,*或/中的一个。在 此外,您需要重载流插入运算符<< 打印此类对象。还必须定义构造函数 作为重载赋值运算符以允许隐式 从双打转换为复杂。您认为的任何其他方法 适当的也应包括在内。你的课程越完整 更好。
Java版本没有那么多方法,因为Java没有 允许操作员重载或朋友功能。再一次,越多 完善你的Java类更好。重写toString()方法。
Python版本还应该包含转换功能 从复合体到字符串。
此项目所需的文件是:complex.h文件 包含复杂类的声明,一个complex.cc文件 包含在中声明的方法和函数的实现 复杂类,一个实例化复数和测试的main.cc 所有方法和函数,一个是Java的Complex.java文件 实现,以及实例化和测试所有的Main.java文件 Complex类的方法。所需的python文件是 complex.py文件。
他向我们提供了以下代码:
/*
*
* Java version
*
*/
/* Main.java */
public class Main {
public static void main(String[] args) {
Rational a = new Rational(1, 2);
Rational b = new Rational(2, 3);
int i = 5;
System.out.println(a + " + " + b + " = " + a.add(b));
System.out.println(a + " - " + b + " = " + a.sub(b));
System.out.println(a + " * " + b + " = " + a.mul(b));
System.out.println(a + " / " + b + " = " + a.div(b));
System.out.println(a + " + " + i + " = " + a.add(i));
System.out.println(a + " - " + i + " = " + a.sub(i));
System.out.println(a + " * " + i + " = " + a.mul(i));
System.out.println(a + " / " + i + " = " + a.div(i));
}
}
/* Rational.java */
public class Rational {
public Rational() {
this(0);
}
public Rational(int num) {
this(num, 1);
}
public Rational(int num, int den) {
this.num = num;
this.den = den;
}
public Rational add(Rational o) {
return new Rational(num * o.den + o.num * den, den * o.den);
}
public Rational add(int n) {
return new Rational(num + n * den, den);
}
public Rational div(Rational o) {
return new Rational(num * o.den, den * o.num);
}
public Rational div(int n) {
return new Rational(num, den * n);
}
public Rational mul(Rational o) {
return new Rational(num * o.num, den * o.den);
}
public Rational mul(int n) {
return new Rational(num * n, den);
}
public Rational sub(Rational o) {
return new Rational(num * o.den - o.num * den, den * o.den);
}
public Rational sub(int n) {
return new Rational(num - n * den, den);
}
public String toString() {
return "(" + num + " / " + den + ")";
}
private int den;
private int num;
}
/*
*
* C++ version
*
*/
/* rational.h */
#ifndef RATIONAL_H
#define RATIONAL_H
#include <iostream>
using std::ostream;
struct rational {
rational(int = 0, int = 1);
rational operator+(const rational &) const;
rational operator-(const rational &) const;
rational operator*(const rational &) const;
rational operator/(const rational &) const;
rational operator+(int) const;
rational operator-(int) const;
rational operator*(int) const;
rational operator/(int) const;
friend rational operator+(int, const rational &);
friend rational operator-(int, const rational &);
friend rational operator*(int, const rational &);
friend rational operator/(int, const rational &);
friend ostream &operator<<(ostream &, const rational &);
private:
int den;
int num;
};
#endif /* RATIONAL_H */
/* rational.cc */
#include <iostream>
#include "rational.h"
rational::rational(int num, int den) : num(num), den(den) {}
rational rational::operator+(const rational &o) const {
return rational(num * o.den + o.num * den, den * o.den);
}
rational rational::operator+(int n) const {
return rational(num + n * den, den);
}
rational rational::operator-(const rational &o) const {
return rational(num * o.den - o.num * den, den * o.den);
}
rational rational::operator-(int n) const {
return rational(num - n * den, den);
}
rational rational::operator*(const rational &o) const {
return rational(num * o.num, den * o.den);
}
rational rational::operator*(int n) const {
return rational(num * n, den);
}
rational rational::operator/(const rational &o) const {
return rational(num * o.den, den * o.num);
}
rational rational::operator/(int n) const {
return rational(num, den * n);
}
rational operator+(int n, const rational &o) {
return o + n;
}
rational operator-(int n, const rational &o) {
return rational(n) - o;
}
rational operator*(int n, const rational &o) {
return o * n;
}
rational operator/(int n, const rational &o) {
return rational(n) / o;
}
ostream &operator<<(ostream &out, const rational &o) {
out << '(' << o.num << " / " << o.den << ')';
return out;
}
/* main.cc */
#include <iostream>
#include "rational.h"
using std::cout;
using std::endl;
int main(void) {
rational a(1, 2);
rational b(2, 3);
int i = 5;
cout << a << " + " << b << " = " << a + b << endl;
cout << a << " - " << b << " = " << a - b << endl;
cout << a << " * " << b << " = " << a * b << endl;
cout << a << " / " << b << " = " << a / b << endl;
cout << a << " + " << i << " = " << a + i << endl;
cout << a << " - " << i << " = " << a - i << endl;
cout << a << " * " << i << " = " << a * i << endl;
cout << a << " / " << i << " = " << a / i << endl;
cout << i << " + " << a << " = " << i + a << endl;
cout << i << " - " << a << " = " << i - a << endl;
cout << i << " * " << a << " = " << i * a << endl;
cout << i << " / " << a << " = " << i / a << endl;
return 0;
}
#
#
# Python version
#
#
class rational:
def __init__(self, num=0, den=1):
self.num = num
self.den = den
def __add__(self, other):
if isinstance(other, int):
return rational(self.num + other * self.den, self.den)
elif isinstance(other, rational):
return rational(self.num * other.den + other.num * self.den, self.den * other.den)
else:
raise TypeError
def __truediv__(self, other):
if isinstance(other, int):
return rational(self.num, self.den * other)
elif isinstance(other, rational):
return rational(self.num * other.den, self.den * other.num)
else:
raise TypeError
def __float__(self):
return float(self.num) / self.den
def __int__(self):
return self.num / self.den
def __mul__(self, other):
if isinstance(other, int):
return rational(self.num * other, self.den)
elif isinstance(other, rational):
return rational(self.num * other.num, self.den * other.den)
else:
raise TypeError
def __radd__(self, other):
return self + other
def __rtruediv__(self, other):
return rational(other) / self
def __rmul__(self, other):
return self * other
def __rsub__(self, other):
return rational(other) - self
def __str__(self):
return '(' + str(self.num) + ' / ' + str(self.den) + ')'
def __sub__(self, other):
if isinstance(other, int):
return rational(self.num - other * self.den, self.den)
elif isinstance(other, rational):
return rational(self.num * other.den - other.num * self.den, self.den * other.den)
else:
raise TypeError
if __name__ == '__main__':
a = rational(1, 2)
b = rational(2, 3)
i = 5
print('%s + %s = %s' % (a, b, a + b))
print('%s - %s = %s' % (a, b, a - b))
print('%s * %s = %s' % (a, b, a * b))
print('%s / %s = %s' % (a, b, a / b))
print('%s + %i = %s' % (a, i, a + i))
print('%s - %i = %s' % (a, i, a - i))
print('%s * %i = %s' % (a, i, a * i))
print('%s / %i = %s' % (a, i, a / i))
print('%i + %s = %s' % (i, a, i + a))
print('%i - %s = %s' % (i, a, i - a))
print('%i * %s = %s' % (i, a, i * a))
print('%i / %s = %s' % (i, a, i / a))
答案 0 :(得分:0)
转换为字符串只是为了以人类可读的形式显示数字。这是在理性类中:return "(" + num + " / " + den + ")";
打印例如(5 / 8)
。您的复杂类可以使toString方法输出( 5 + 8i )
将复数乘以数字(double)是一个有效的操作,它会产生另一个复数。
将复数乘以实数:
(x + yi) u = xu + yu i.
使用他给出的代码,您可以为Rational数字完成相同的赋值(定义为两个数字num和den)。您需要将该代码调整为复数,这些复数也被定义为几个数字。
答案 1 :(得分:0)
我不明白double在哪里。
我认为它是一个普通的double
浮点值,而不是复数值。
此外,python版本应该将复合体转换为字符串,我再也不明白它的要求。
我假设使用String而不是名为Complex的自定义类。
除非你另有所知,否则我会这样认为。它是说将字符串(整数?)字面转换为字符串数据类型?
答案 2 :(得分:0)
复数包含实部和虚部,均存储为双精度。既然你说你已经知道了这些,我就不会详细介绍了,但是快速谷歌揭示了你几乎要完成的复杂数字类的许多Java实现。
http://introcs.cs.princeton.edu/java/97data/Complex.java.html
以前我用过的一个例子,它符合你的要求:
public Complex times(Complex b)
public Complex times(double alpha)
这些方法将采用复数或α应用于实部和虚部,并返回复数。
对于python字符串部分,我认为他希望你采用真实和想象的部分,并以一种人类可读的形式表达它们:一个字符串
希望我能帮到你 md_5答案 3 :(得分:0)
当受让人说
时op:Complex×Complex→Complex op:复合×双→复合操作: double×Complex→Complex 其中op是+, - ,*或/之一。
这意味着您必须在复数的夫妻之间以及在Real和Complex的混合夫妻之间实施所有二元操作。例如
*:复杂×双→复杂
你应该写一些类似的东西:
Complex operator*(Complex z, double t) {
return Complex(t * z.Real(), t * z.Imag());
}