Question

我正在尝试为我的viewModel创建一个通用Container，因此可以在没有viewModel特定知识的情况下将常用方法应用于各种对象。容器和包含的对象如下所示：

var containedViewModel = function() {
  var self = this;
  self.id = ko.observable();
    ...
  self.doSomething = function() {
  alert('here');
  };

}

var ContainerModel = function(cRoot, cModel, cName) {
  var self = this;

  self.rootModel  = cRoot;                       // Root view model
  self.viewName   = cName;                       // viewModel container name
  self.refModel   = cModel;                      // viewModel reference
  self.viewModel  = ko.observable();             // Single view model
  self.viewModels = ko.observableArray();        // Array of view models

  self.init = function(rootModel) {
    self.viewModel = new self.refModel();
  } 
  self.doSomething = function() {
    self.rootModel.doSomeThing();    // This works
    self.refModel.doSomeThing();     // This does not work
    self.viewModel.doSomeThing();    // This does not work as well
  }

}

将使用以下调用创建容器：

var ParnentModel = function() {
  var self = this;
  self.id = ko.observable();
    ...
  self.container = new ContainerModel(self, containedViewModel, 'modelName');
    ...
  self.doSomething = function() {
  alert('here');
  };
};

在此示例中，rootModel函数访问正常，因为创建了实际的viewmodel并将其传递给容器。使用'new self.refModel（）'和'self.rootModel.doSomeThing（）'似乎按预期工作。当我尝试使用'self.viewModel.doSomeThing（）;'淘汰赛抱怨说这不是一个功能。

是否可以通过引用viewModel来访问viewModels函数。

任何帮助将不胜感激。

Answer 1

你快到了。请参阅我在代码中的评论。

var containedViewModel = function() {
  var self = this;
  self.id = ko.observable();
  self.doSomething = function() {
    alert('contained');
  };
  // I would prefer to have return self here
};

var ContainerModel = function(cRoot, cModel, cName) {
  var self = this;

  self.rootModel  = cRoot;                       // Root view model
  self.viewName   = cName;                       // viewModel container name
  self.refModel   = cModel;                      // viewModel reference
  self.viewModel  = ko.observable();             // Single view model
  self.viewModels = ko.observableArray();        // Array of view models

  self.init = function(rootModel) {
    // you meant this, right?
    self.viewModel(new self.refModel());
  }; 
  self.doSomething = function() {
    self.rootModel.doSomething();    // This works
    //self.refModel.doSomeThing();     // This does not work
    // need to unwrap the value, fixed typo
    self.viewModel().doSomething();    // This does not work as well
  };
};

var ParnentModel = function() {
  var self = this;
  self.id = ko.observable();
  self.container = new ContainerModel(self, containedViewModel, 'modelName');
  // missing call to init
  self.container.init();
  self.doSomething = function() {
      alert('parent');
  };
};

// execution
var p = new ParnentModel();
p.container.doSomething();

http://jsbin.com/arezew/1/edit

Answer 2

我认为你应该在传递给ContainerModel时创建包含模型的实例：

self.container = new ContainerModel(self, new containedViewModel, 'modelName');

按原型访问viewModel函数

2 个答案: