我无法弄清楚如何将信息级别的消息记录到stdout,但其他一切都记录到stderr。我已经读过http://docs.python.org/library/logging.html了。有什么建议吗?
答案 0 :(得分:97)
以下脚本log1.py
:
import logging, sys
class SingleLevelFilter(logging.Filter):
def __init__(self, passlevel, reject):
self.passlevel = passlevel
self.reject = reject
def filter(self, record):
if self.reject:
return (record.levelno != self.passlevel)
else:
return (record.levelno == self.passlevel)
h1 = logging.StreamHandler(sys.stdout)
f1 = SingleLevelFilter(logging.INFO, False)
h1.addFilter(f1)
rootLogger = logging.getLogger()
rootLogger.addHandler(h1)
h2 = logging.StreamHandler(sys.stderr)
f2 = SingleLevelFilter(logging.INFO, True)
h2.addFilter(f2)
rootLogger.addHandler(h2)
logger = logging.getLogger("my.logger")
logger.setLevel(logging.DEBUG)
logger.debug("A DEBUG message")
logger.info("An INFO message")
logger.warning("A WARNING message")
logger.error("An ERROR message")
logger.critical("A CRITICAL message")
运行时,会产生以下结果。
C:\temp>log1.py A DEBUG message An INFO message A WARNING message An ERROR message A CRITICAL message
正如您所期望的那样,因为终端sys.stdout
和sys.stderr
是相同的。现在,让我们将stdout重定向到文件tmp
:
C:\temp>log1.py >tmp A DEBUG message A WARNING message An ERROR message A CRITICAL message
因此INFO消息尚未打印到终端 - 但是已经打印了导向sys.stderr
的消息。让我们来看看tmp
中的内容:
C:\temp>type tmp An INFO message
所以这种方法似乎可以做你想要的。
答案 1 :(得分:12)
一般来说,我认为将低于WARNING
的邮件重定向到 stdout ,而非只有INFO
条消息才有意义。
基于 Vinay Sajip 的优秀答案,我想出了这个:
class MaxLevelFilter(Filter):
'''Filters (lets through) all messages with level < LEVEL'''
def __init__(self, level):
self.level = level
def filter(self, record):
return record.levelno < self.level # "<" instead of "<=": since logger.setLevel is inclusive, this should be exclusive
MIN_LEVEL= DEBUG
#...
stdout_hdlr = StreamHandler(sys.stdout)
stderr_hdlr = StreamHandler(sys.stderr)
lower_than_warning= MaxLevelFilter(WARNING)
stdout_hdlr.addFilter( lower_than_warning ) #messages lower than WARNING go to stdout
stdout_hdlr.setLevel( MIN_LEVEL )
stderr_hdlr.setLevel( max(MIN_LEVEL, WARNING) ) #messages >= WARNING ( and >= STDOUT_LOG_LEVEL ) go to stderr
#...
答案 2 :(得分:10)
由于我的编辑被拒绝了,所以这是我的答案。 @ goncalopp的答案很好,但并不孤立或开箱即用。这是我的改进版本:
import sys, logging
class LogFilter(logging.Filter):
"""Filters (lets through) all messages with level < LEVEL"""
# http://stackoverflow.com/a/24956305/408556
def __init__(self, level):
self.level = level
def filter(self, record):
# "<" instead of "<=": since logger.setLevel is inclusive, this should
# be exclusive
return record.levelno < self.level
MIN_LEVEL = logging.DEBUG
stdout_hdlr = logging.StreamHandler(sys.stdout)
stderr_hdlr = logging.StreamHandler(sys.stderr)
log_filter = LogFilter(logging.WARNING)
stdout_hdlr.addFilter(log_filter)
stdout_hdlr.setLevel(MIN_LEVEL)
stderr_hdlr.setLevel(max(MIN_LEVEL, logging.WARNING))
# messages lower than WARNING go to stdout
# messages >= WARNING (and >= STDOUT_LOG_LEVEL) go to stderr
rootLogger = logging.getLogger()
rootLogger.addHandler(stdout_hdlr)
rootLogger.addHandler(stderr_hdlr)
logger = logging.getLogger(__name__)
logger.setLevel(logging.DEBUG)
# Example Usage
>>> logger.debug("A DEBUG message")
>>> logger.info("An INFO message")
>>> logger.warning("A WARNING message")
>>> logger.error("An ERROR message")
>>> logger.critical("A CRITICAL message")
答案 3 :(得分:0)
尝试这个猴子补丁~~
import sys
import logging
import threading
def _logging_handle(self, record):
self.STREAM_LOCKER = getattr(self, "STREAM_LOCKER", threading.RLock())
if self.stream in (sys.stdout, sys.stderr) and record.levelname in self.FIX_LEVELS:
try:
self.STREAM_LOCKER.acquire()
self.stream = sys.stdout
self.old_handle(record)
self.stream = sys.stderr
finally:
self.STREAM_LOCKER.release()
else:
self.old_handle(record)
def patch_logging_stream(*levels):
"""
writing some logging level message to sys.stdout
example:
patch_logging_stream(logging.INFO, logging.DEBUG)
logging.getLogger('root').setLevel(logging.DEBUG)
logging.getLogger('root').debug('test stdout')
logging.getLogger('root').error('test stderr')
"""
stream_handler = logging.StreamHandler
levels = levels or [logging.DEBUG, logging.INFO]
stream_handler.FIX_LEVELS = [logging.getLevelName(i) for i in levels]
if hasattr(stream_handler, "old_handle"):
stream_handler.handle = stream_handler.old_handle
stream_handler.old_handle = stream_handler.handle
stream_handler.handle = _logging_handle
测试
#
patch_logging_stream(logging.INFO, logging.DEBUG)
logging.getLogger('root').setLevel(logging.DEBUG)
logging.getLogger('root').debug('test root stdout')
logging.getLogger('root').error('test root stderr')
测试输出
$ python3 test_patch_logging.py 2>/dev/null
DEBUG:root:test root stdout
$ python3 test_patch_logging.py 1>/dev/null
ERROR:root:test root stderr
答案 4 :(得分:0)
最简单的处理程序,将彩色输出发送到stderr:
class ColorStderr(logging.StreamHandler):
def __init__(self):
class AddColor(logging.Formatter):
def format(self, record: logging.LogRecord):
msg = super().format(record)
# Green/Cyan/Yellow/Red/Redder based on log level:
color = '\033[1;' + ('32m', '36m', '33m', '31m', '41m')[
min(4,int(4 * record.levelno / logging.FATAL))]
return color + record.levelname + '\033[1;0m: ' + msg
super().__init__(sys.stderr)
self.setFormatter(AddColor())
用于:
logging.basicConfig(level=logging.INFO, handlers=[ColorStderr()])
或者您甚至可以将格式化程序直接应用于当前的日志处理程序,而无需使用ColorStderr
:
logging.getLogger().handlers[0].setFormatter(AddColor())