有没有办法使用NULL
将列设置为$wpdb->update();
?
当我尝试时,WordPress会尝试将该列强制转换为浮点数,将NULL
转换为0
。
我检查了核心代码和$wpdb->update()
内部,$format
参数只期望%s,%f和%d。我甚至将$wpdb->field_types['myCol']
设置为'NULL'
,但两者都只用于打破$wpdb->update()
的查询(有趣的是,它会在{{1}之后移动每列的值。 }})。
此处有一个相关问题,但该答案仅涉及NULL
,不 INSERT
。
从数据完整性的角度来看,UPDATE
对于此列非常重要,因此我必须能够在必要时对其进行设置。
答案 0 :(得分:1)
正如您自己所说,$format
参数只期待%s
,%f
和%d
。整个事情将通过prepare
传递,它也不会采用null
格式说明符,因为它基本上接受(v)(s)printf
接受但没有参数交换的相同格式说明符。您无法通过NULL
通过update
。你有the post suggested as a possible duplicate中提到的相同选择,实质上它是。
update
功能。编写自己的SQL并将其与$wpdb->query
一起使用。如果您正在处理自己的表格,那应该没问题。$wpdb
。答案 1 :(得分:0)
这是一个从最新版本的wordpress修改wpdb的解决方案,以便允许使用insert()和update()将空值插入和更新到SQL表中:
/*
* Fix wpdb to allow inserting/updating of null values into tables
*/
class wpdbfixed extends wpdb
{
function insert($table, $data, $format = null) {
$type = 'INSERT';
if ( ! in_array( strtoupper( $type ), array( 'REPLACE', 'INSERT' ) ) )
return false;
$this->insert_id = 0;
$formats = $format = (array) $format;
$fields = array_keys( $data );
$formatted_fields = array();
foreach ( $fields as $field ) {
if ( !empty( $format ) )
$form = ( $form = array_shift( $formats ) ) ? $form : $format[0];
elseif ( isset( $this->field_types[$field] ) )
$form = $this->field_types[$field];
else
$form = '%s';
//***edit begin here***
if ($data[$field]===null) {
unset($data[$field]); //Remove this element from array, so we don't try to insert its value into the %s/%d/%f parts during prepare(). Without this, array would become shifted.
$formatted_fields[] = 'NULL';
} else {
$formatted_fields[] = $form; //Original line of code
}
//***edit ends here***
}
$sql = "{$type} INTO `$table` (`" . implode( '`,`', $fields ) . "`) VALUES (" . implode( ",", $formatted_fields ) . ")";
return $this->query( $this->prepare( $sql, $data ) );
}
function update($table, $data, $where, $format = null, $where_format = null)
{
if ( ! is_array( $data ) || ! is_array( $where ) )
return false;
$formats = $format = (array) $format;
$bits = $wheres = array();
foreach ( (array) array_keys( $data ) as $field ) {
if ( !empty( $format ) )
$form = ( $form = array_shift( $formats ) ) ? $form : $format[0];
elseif ( isset($this->field_types[$field]) )
$form = $this->field_types[$field];
else
$form = '%s';
//***edit begin here***
if ($data[$field]===null)
{
unset($data[$field]); //Remove this element from array, so we don't try to insert its value into the %s/%d/%f parts during prepare(). Without this, array would become shifted.
$bits[] = "`$field` = NULL";
} else {
$bits[] = "`$field` = {$form}"; //Original line of code
}
//***edit ends here***
}
$where_formats = $where_format = (array) $where_format;
foreach ( (array) array_keys( $where ) as $field ) {
if ( !empty( $where_format ) )
$form = ( $form = array_shift( $where_formats ) ) ? $form : $where_format[0];
elseif ( isset( $this->field_types[$field] ) )
$form = $this->field_types[$field];
else
$form = '%s';
$wheres[] = "`$field` = {$form}";
}
$sql = "UPDATE `$table` SET " . implode( ', ', $bits ) . ' WHERE ' . implode( ' AND ', $wheres );
return $this->query( $this->prepare( $sql, array_merge( array_values( $data ), array_values( $where ) ) ) );
}
}
global $wpdb_allow_null;
$wpdb_allow_null = new wpdbfixed(DB_USER, DB_PASSWORD, DB_NAME, DB_HOST);
将此代码插入总是运行的地方,例如您的functions.php,然后正常使用新的全局$ wpdb_allowed_null-> insert()和 - > update()。
我更喜欢这样做而不是覆盖默认的$ wpdb,以保留其他Wordpress和其他插件所期望的数据库行为。